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Natasha_Volkova [10]
3 years ago
5

10 pts

Mathematics
1 answer:
Simora [160]3 years ago
4 0
Area = pi * radius^2
radius = diameter/2 = 26/2 = 13 feet

Area = 3.14 * (13^2)
Area = 3.14 * 169 = 530.66 ft^2
You might be interested in
A RECTANGULAR PRISM HAS A VOLUME OF 96 FT. THE AREA OF THE BASE IS 24 FT. WHAT IS THE HEIGHT OF THE PRISM?
Reptile [31]
96
i hope it is right answer ;)
6 0
3 years ago
1)<br> I<br> I<br> ? 20-<br> A) 999<br> C) 1219<br> B) 39°<br> D) 1020
WITCHER [35]

Answer:

C

Step-by-step explanation:

\angle{VUW} = 180 - 141 = 39

\angle{WVU} = 180 - (20 + 39) = 121

Answer: 121

8 0
3 years ago
What is the width of the rectangle shown?
nika2105 [10]
I think the answer is 2( 4x+3)(x-2)
7 0
3 years ago
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
What are the significant digits in 0.00025km?
brilliants [131]
Anything between the decimal and last non-zero digit
so 00025 are significant
the 0 in front is insignificant because it could be
00000.00025

zeroes after the 25 don't matter becasue it could be
0.000250000000 and it wouldn't change


the sig figs are 00025
4 0
3 years ago
Read 2 more answers
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