360 degrees. I'm pretty sure
Answer:
Explanation:
From the given information:
At state 1:
Initial Quality ![= x_1 = 0.85](https://tex.z-dn.net/?f=%3D%20x_1%20%3D%200.85)
mass = 10.0 kg
At state 2:
Temperature ![T_2 = 320^0](https://tex.z-dn.net/?f=T_2%20%3D%20320%5E0)
mass of the piston ![m_p = 204 \ kg](https://tex.z-dn.net/?f=m_p%20%3D%20204%20%5C%20kg)
area of the piston ![A_p = 0.00 5 \ m^2](https://tex.z-dn.net/?f=A_p%20%3D%200.00%205%20%5C%20m%5E2)
Atmospheric pressure ![P_{atm}= 100 \ kPa = 100 \times 10^3 \ Pa](https://tex.z-dn.net/?f=P_%7Batm%7D%3D%20100%20%5C%20kPa%20%3D%20100%20%5Ctimes%2010%5E3%20%5C%20Pa)
Gravitational acceleration = 9.81 m/s²
, This is because there exists no restriction to the movement of the piston and provided the process is frictionless. So, the process 1-2 is regarded as constant.
To calculate the applying force balance over the piston by using force balance in the vertical direction:
![\mathbf{P_{AP} = P_{atmA_p} + m_pg}](https://tex.z-dn.net/?f=%5Cmathbf%7BP_%7BAP%7D%20%3D%20P_%7BatmA_p%7D%20%2B%20m_pg%7D)
∴
(100 × 10³)×0.005 + 204 × 9.31 = P × 0.05
P = 500248 Pa
P = 500.25 kPa
At state 1:
![\mathbf{P_1 = P = 500.25 \ kPa}](https://tex.z-dn.net/?f=%5Cmathbf%7BP_1%20%3D%20P%20%3D%20500.25%20%5C%20kPa%7D)
![x_1 = 0.85](https://tex.z-dn.net/?f=x_1%20%3D%200.85)
Hence, this is a saturated mixture of liquid and vapor
Using the steam tables at 500.25 kPa
![V_f = 1.093 \times 10^{-3} \ m^3/kg \\ \\ V_g = 0.375 \ m^3/kg \\ \\ U_f = 639.72 \ kJ/kg \\ \\ U_g = 2560.72 \ kJ/kg](https://tex.z-dn.net/?f=V_f%20%3D%201.093%20%5Ctimes%2010%5E%7B-3%7D%20%5C%20m%5E3%2Fkg%20%5C%5C%20%5C%5C%20%20V_g%20%3D%200.375%20%5C%20m%5E3%2Fkg%20%5C%5C%20%5C%5C%20U_f%20%3D%20639.72%20%5C%20kJ%2Fkg%20%5C%5C%20%5C%5C%20U_g%20%3D%202560.72%20%5C%20kJ%2Fkg)
∴
Specific volume at state 1 is given as:
![V_1 = [ V_f +x_1(v_g -v_f) ] \ at \ 500.25 \ kPa \\ \\ V_1 = 0.319 \ m^3/kg](https://tex.z-dn.net/?f=V_1%20%3D%20%5B%20V_f%20%2Bx_1%28v_g%20-v_f%29%20%5D%20%20%5C%20at%20%5C%20500.25%20%5C%20kPa%20%5C%5C%20%5C%5C%20%20V_1%20%3D%200.319%20%5C%20m%5E3%2Fkg)
volume at state 1 is given by:
![V_1 = mV_1 = 10 \times 0.319 \\ \\ V_1 = 3.19 \ m^3](https://tex.z-dn.net/?f=V_1%20%3D%20mV_1%20%3D%2010%20%5Ctimes%200.319%20%20%20%5C%5C%20%5C%5C%20%20V_1%20%3D%203.19%20%5C%20m%5E3)
Similarly, the specific internal energy is:
![U_1 = [U_f +x_1 (U_o-Uf)] \ at \ 500.25 \ kPa](https://tex.z-dn.net/?f=U_1%20%3D%20%5BU_f%20%2Bx_1%20%28U_o-Uf%29%5D%20%20%5C%20at%20%5C%20500.25%20%5C%20kPa)
![U_1 = 639.72 +0.82 (2560.72 -639.72)](https://tex.z-dn.net/?f=U_1%20%3D%20639.72%20%2B0.82%20%282560.72%20-639.72%29)
![U_1 = 2272.57 \ kJ/kg](https://tex.z-dn.net/?f=U_1%20%3D%202272.57%20%5C%20kJ%2Fkg)
At state 2:
![P = P_1 = P_2 = 500.25 \ kPa \\ \\ T_2 = 320^0 \ C](https://tex.z-dn.net/?f=P%20%3D%20P_1%20%3D%20P_2%20%3D%20500.25%20%5C%20kPa%20%5C%5C%20%5C%5C%20T_2%20%3D%20320%5E0%20%5C%20C)
Using steam tables at P = 500.25 kPa and T = 320° C
![V_2 = 0.541 \ m^3/kg \\ \\ U_2 = 2835.08 \ kJ/kg](https://tex.z-dn.net/?f=V_2%20%3D%200.541%20%5C%20m%5E3%2Fkg%20%20%5C%5C%20%5C%5C%20U_2%20%3D%202835.08%20%5C%20kJ%2Fkg)
∴
![V_2 = mV-2 = 10 \times V_2 = 5.41 \ m^3](https://tex.z-dn.net/?f=V_2%20%3D%20mV-2%20%3D%2010%20%5Ctimes%20V_2%20%3D%205.41%20%5C%20m%5E3)
![\text{Now; Applying the 1st law of thermodynamics to the system}](https://tex.z-dn.net/?f=%5Ctext%7BNow%3B%20Applying%20the%201st%20law%20of%20thermodynamics%20to%20the%20system%7D)
![_1Q_2 -_1W_2 = \Delta V =m(u_2-u_1) \\ \\ where;\ _1W_2 = P(V_2-V_1) \\ \\ _1Q_2 -P(V_2-V_1) = m(u_2-u_1) \\ \\ _1Q_2 - 500.25(5.91 -3.19) = 10( 2835.08 -2272.57) \\ \\ \mathbf{ _1Q_2 = 6735.66 \ kJ}](https://tex.z-dn.net/?f=_1Q_2%20-_1W_2%20%3D%20%5CDelta%20V%20%3Dm%28u_2-u_1%29%20%5C%5C%20%5C%5C%20%20where%3B%5C%20%20_1W_2%20%3D%20P%28V_2-V_1%29%20%5C%5C%20%5C%5C%20%20_1Q_2%20-P%28V_2-V_1%29%20%20%3D%20m%28u_2-u_1%29%20%5C%5C%20%5C%5C%20_1Q_2%20%20-%20500.25%285.91%20-3.19%29%20%3D%2010%28%202835.08%20-2272.57%29%20%5C%5C%20%5C%5C%20%5Cmathbf%7B%20_1Q_2%20%3D%206735.66%20%5C%20kJ%7D)
Answer:
All of the objects in the solar system orbit the
Explanation:
sun
B. galaxies
Explanation:
Spiral, elliptical, irregular and barred spiral are descriptions of different shapes of galaxies.
A galaxy is a constellation or group of stars.
- A spiral galaxies are the most common and they have spiral arm shapes.
- A barred spiral is made up of spiral shape and bar in the middle.
- Elliptical galaxies are spherical in shape.
- Irregular galaxies are usually not patterned and lacks form.
learn more:
Galaxy recession velocity brainly.com/question/12617031
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