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Ivenika [448]
3 years ago
15

I DONT NEED ANYONE TO ANSWER QUESTION BUT IS THERE ANYONE THAT CAN HELP ME ON QUIZZES FOR FREE

Physics
2 answers:
olchik [2.2K]3 years ago
8 0

Answer:

Sorry

Explanation:

lol i need someone for myself to do that

pochemuha3 years ago
7 0

Answer:

Not me

Explanation:

Sorry

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Which of the rolling statement is not true about proper tire care? A. If you see a weaver bar across the width of the tread. B.
skad [1K]
The correct answer should be <span>A. If you see a wear bar across the width of the tread, it's time to change the tire

This is an incorrect sentence because you should change a tire before you see the wear bar. At the time you see the bar, you should've already changed it. </span>
7 0
3 years ago
How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v
777dan777 [17]
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
W= qV_i - qV_f
where q is the charge of the proton, q=1 e = 1.6\cdot 10^{-19}C, with e being the elementary charge, and V_i = +125 V and V_f = -55 V are the initial and final voltage.

Substituting, we get (in electronvolts):
W=e(125 V-(-55 V))=180 eV
and in Joule:
W=(1.6 \cdot 10^{-19})(125 V-(-55V))=2.88 \cdot 10^{-17}J

5 0
3 years ago
A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the pers
Inessa [10]

Answer:

    v₁ = -0.8087 m / s

Explanation:

To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved

Initial instant. When they are united

        p₀ = 0

Final moment. After throwing the brick

        p_{f} = (m_man + m_skate) v1 + m_brick v2

the moment is preserved

        p₀ = p_{f}

        0 = (m_man + m_skate) v₁ + m_brick v₂

        v₁ = -  \frac{ m_{brick}   }{m_{man} + m_{skate}   }  v_{2}

the negative sign indicates that the two speeds are in the opposite direction

let's calculate

        v₁ = - \frac{2.5}{67 + 4.10}  23.0

        v₁ = -0.8087 m / s

6 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
Cyclotrons are widely used in nuclear medicine for producing short-lived radioactive isotopes. These cyclotrons typically accele
lyudmila [28]

Answer:

Part a)

v = 3.16 \times 10^7 m/s

Part b)

r = 0.166 m

Explanation:

Part a)

As we know that the energy of the Hydride ion is given as

E = 5 MeV

here we have

\frac{1}{2}mv^2 = 5\times 10^6(1.6 \times 10^{-19})

also we know that

m = 1.6 \times 10^{-27} kg

now we have

v = \sqrt{\frac{2 \times 5 \times 10^6(1.6 \times 10^{-19}}{1.6\times 10^{-27}}

v = 3.16 \times 10^7 m/s

Part b)

As we know that magnetic force on the charge is centripetal force

so we have

qvB = \frac{mv^2}{r}

so we have

r = \frac{mv}{qB}

so we have

r = \frac{1.6 \times 10^{-27}(3.16 \times 10^7)}{(1.6 \times 10^{-19}) 1.9}

r = 0.166 m

4 0
3 years ago
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