Answer:
you got this kiddo
Step-by-step explanation:
<span>1) Multiply both sides of the equation by 2:
2(A)=2[1/2h(b+c)
2A=2/2h(b+c)
2A=1h(b+c)
2A=h(b+c)
2) Divide both sides of the equation by (b+c):
(2A)/(b+c)=[h(b+c)]/(b+c)
2A/(b+c)=h
h=2A/(b+c)
Answer: </span>
The derivative of inverse trigonometric identities follow<span> a set of rules. </span>
<span>For </span>arc cos<span> x, the </span>dy/dx is equal to -1/ square root of (1 - x2).
<span>In this case, we still have 1/2 x inside the angle quantity so we multiply the </span>dy/dx above with 1/2. Hence, y' = is -1<span>/ 2 square root of (1 - x2); x = 1, y' is infinity. this means the line is horizontal. The answer hence is y = 1.</span>