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wel
3 years ago
14

Please help me so much quick :)

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

22 < x < 74

Step-by-step explanation:

Given 2 sides of a triangle with third side x , then

difference of 2 sides < x < sum of 2 sides , that is

48 - 26 < x < 48 + 26 , so

22 < x < 74

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A coach gives her players the option of running around feel twice or around the entire stadium once the following diagram shows
BARSIC [14]

Answer:

Distance around the stadium is 75.16 monger than the field

Step-by-step explanation:

From the graph attached,

Coordinates of A → (-10, 60)

Coordinates of B → (60, -10)

Coordinates of C → (10, -60)

Coordinates of D → (-60, 10)

Perimeter of field = AB + BC + CD + DA

Since field is in the shape of a rectangle,

AB = CD and BC = DA

Therefore, perimeter of the rectangle = 2(AB + BC)

Length of AB = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

                      = \sqrt{(60+10)^2+(-10-60)^2}

                      = \sqrt{2(70)^{2} }

                      = 70\sqrt{2} m

Length of BC = \sqrt{(60-10)^2+(-10+60)^2}

                      = 50\sqrt{2} m

Perimeter of ABCD = 2(70√2 + 50√2)

                                = 240√2 m

                                = 339.41 m

Perimeter of stadium = 2πr      [Here, r = radius of the circle]

                                   = 2π(120)

                                   = 753.98 m

To run around the field twice, distance covered by the players = 2(339.41)

= 678.82 m

Difference in the distance covered to run around the stadium and the rectangular field = 753.98 - 678.82

                            = 75.16 m

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3 years ago
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4 tsp = _ tbsp _ tsp
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4 tsp = _ tbsp _ tsp

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