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notka56 [123]
3 years ago
6

If your Indiana trip is 375 km, how many cm is this ?

Mathematics
2 answers:
Ivan3 years ago
7 0

Answer:

The answer is 3.75e+7

Step-by-step explanation:

Katarina [22]3 years ago
6 0

Answer:

The correct answer is 375 km =  3.75e + 7 cm

Step-by-step explanation:

<u>km to cm conversion</u>

Multiply the length value by 100000

It is given that,  Indiana trip is 375 km

<u>To convert 375 km to cm</u>

Here length in km

length = 375 km

<u>length * </u>100000 = 375 * 100000

= 37500000

= 3.75e + 7 cm

Therefore the correct answer is 375 km =  3.75e + 7 cm

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The table is shows the fraction of the votes that each candidate received. If 230 students voted, how many students voted for ea
barxatty [35]

3/5 * 230 = 138 votes for Nyemi

3/10 * 230 = 69 votes for Luke

1/10 * 230 = 23 votes for Natalie

***************** DOUBLE-CHECK ****************

138 + 69 + 23 = 230  Correct!!


6 0
3 years ago
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Can someone help me ASP.
Ivahew [28]

Answer:

The anwsers are

a- trapezoid

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8 0
4 years ago
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Sage and Tom started the month with the same number of talk minutes on their cell phones. Sage talked for 7 minutes with her dad
Paraphin [41]

Answer:

a. Sage and Tom have the same number of talk minutes left on their cell phone plans.

b. y = x - 7

Explanation:

Sage talked for 7 minutes with her dad.

Tom talked for 4 minutes with a friend and 3 more minutes with his mom which means he spoke for :

= 4 + 3

= 7 minutes

They both spoke for 7 minutes and therefore have the same amount of time left.

Algebraic expression:

Assuming the time Tom started with is denoted by x and the time he is left with is denoted by y.

The expression is:

y = x - 7

6 0
3 years ago
The percent frequency for S&amp;P 100 companies in the Consumer Staples sector is
torisob [31]

The percent frequency for S&P 100 companies in the Consumer Staples sector is 8.2%

<h3>How to determine the percentage frequency?</h3>

From the pie chart of the dataset (see attachment for the pie chart), we have:

Consumer Staples = 8.2%

This means that the percent frequency for S&P 100 companies in the Consumer Staples sector is 8.2%

Read more about pie charts at:

brainly.com/question/24461724

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8 0
2 years ago
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre
melamori03 [73]

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \mu = <u><em>mean power consumption for microwave ovens.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, H_A : \mu > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                                T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean power consumption for ovens = 257.3 W

            σ = population standard deviation = 15 W

            n = sample of microwave ovens = 20

So, <em><u>the test statistics</u></em>  =  \frac{257.3-250}{\frac{15}{\sqrt{20} } }

                                      =  2.176

The value of z test statistics is 2.176.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

7 0
3 years ago
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