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2 years ago

Which represents the solution(s) of the equation x2 = 36?

Mathematics

2 answers:

mart [117]2 years ago

7 0

Answer:

Step-by-step explanation:

x2 = 36?

solution

x^2-(36)=0

Factoring: x2-36

Check : 36 is the square of 6

Check : x2 is the square of x1

Factorization is : (x + 6) • (x - 6)

(x + 6) • (x - 6) = 0

x+6 = 0

x = -6

x-6 = 0

add 6 to both side

x = 6

x = -6

Romashka-Z-Leto [24]2 years ago

6 0

Answer:

x=+or-1 hope this help

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Someone please help.

Alexxandr [17]

Hi there!

$f(x)+f(x+1)=4f(x)$

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

1) f(x)

We're given that $f(x)=3^x$ :

⇒ $f(x)=3^x$ :

2) f(x+1)

Now, we must find f(x+1). To do so, add 1 to x in the original function $f(x)=3^x$ :

⇒ $f(x+1)=3^x^+^1$

3) 4f(x)

To find 4f(x), multiply the original function $f(x)=3^x$ by 4:

$4f(x)=4*3^x$ :

4) Put it all together

Now, plug each of the three parts into the equation $f(x)+f(x+1)=4f(x)$ :

$f(x)+f(x+1)=4f(x)$

$3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x$

Factor the left side

$3^x*(1+3)=4*3^x$

Divide both sides by 3^x

$1+3=4\\4=4$

Because this equation is true, $f(x)+f(x+1)=4f(x)$ is therefore true.

I hope this helps!

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