Cross sections of the volume are washers or annuli with outer radii <em>x(y)</em> + 1, where
<em>y</em> = <em>x(y) </em>² - 1 ==> <em>x(y)</em> = √(<em>y</em> + 1)
and inner radii 1. The distance between the outermost edge of each shell to the axis of revolution is then 1 + √(<em>y</em> + 1), and the distance between the innermost edge of <em>R</em> on the <em>y</em>-axis to the axis of revolution is 1.
For each value of <em>y</em> in the interval [-1, 3], the corresponding cross section has an area of
<em>π</em> (1 + √(<em>y</em> + 1))² - <em>π</em> (1)² = <em>π</em> (2√(<em>y</em> + 1) + <em>y</em> + 1)
Then the volume of the solid is the integral of this area over [-1, 3]:


The answer is the second option y= -2x + 11
The problem is actually already factored for you. They are asking you to just set the equation to zero. Find the zeros.
Answer: the 10th term is 4.1
Step-by-step explanation:
The sum is +0.4 each time.
1=0.5
2=0.9
3=1.3
4=1.7
5=2.1
6=2.5
7=2.9
8=3.3
9=3.7
10=4.1