2 years ago

Find the missing angle

Mathematics

1 answer:

liberstina [14]2 years ago

7 0

In a trapezoid the angles add up to 360 so 360-(90+90+65)=115

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Please Help!!! Find the slope of the line that passes through (63, 77) and (-10, -2).

allochka39001 [22]

Answer:

y=79/73x+644/73

theres the equation, enjoy <3

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2 years ago

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3 years ago

What is the vertex of the parabola with the equation y=1/5x^2 + 2x - 8

bixtya [17]

Answer:

(-5,-13)

Step-by-step explanation:

Find the vertex of the parabola y=1/5x^2+2x−8.

In this equation a=15 and b = 2.

x= -2/2(1/5) = -2/2/5 = -2/1 * 5/2 = -5

Substitute −5 into the equation y=1/5x^2+2x−8

y=1/5(−5)^2+2(−5)−8

y=5−10−8

y=−13

The vertex is (−5 , −13)

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2 years ago

¿cuál es el vértice de una parábola que corta los ejes en los puntos (-1,0) , (5,0), (0,-10) ?

kvasek [131]

Answer:

vertex: (2,-18)

Step-by-step explanation:

y = ax² + bx + c

(-1,0) : a - b + c = 0 ...(1)

(5,0) : 25a +5b +c = 0 ...(2)

(0,-10): 0a + 0b + c = -10 c=-10

(1) x5: 5a - 5b + 5c = 0 ...(3)

(2)+(3): 30a + 6c = 0 30a = -6c = 60 a = 2

(1): 2 - b -10 = 0 b = -8

Equation: y = 2x² - 8x -10 = 2 (x² -4x +4) - 18 = 2(x-2)² -18

equation: y = a(x-h)²+k (h,k): vertex

vertex: (2,-18)

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2 years ago

F(x)=x^2(x+3)^2 <br><br> How do I find the roots of this equation?

Genrish500 [490]

= x^2 ( x+3 ) (x+3)
= set equal to 0

X^2= 0
X=0

X+3=0
X=-3

Answer is -3 and 0

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2 years ago