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vlada-n [284]
3 years ago
14

The fact that a strain of yeast with a certain defective gene can use the human version of the gene to repair itself is evidence

that yeast and humans - A) depend on the same food supply B) share a genetic code Eliminate C) both have eukaryotic cells D) have identical genomes
Biology
2 answers:
natulia [17]3 years ago
4 0
Let's look at each individual answer:
A) We know this is factually wrong; humans and yeast eat different things. This question is about the micro-level of molecules, so we cannot infer much about the food of the organisms.
B) This is correct. If we did not share a genetic code, the yeast cell would not have been able to "translate" the genetic information in human genes in order to fix the problem. The genetic code is universal in life as we know it; we can transfer microbial DNA in humans and our cell machinery will still be able to utilize it and this is the basis of DNA recombination.
C) Again, this is not necessary. See the example in B (there are prokaryotic bacteria that illustrate the point).
D) This is plain silly; the genome determines to an extreme part our appearance etc. and it is obvious that we only share a small part of our genome with yeast, and certainly not all of it!
jeka943 years ago
4 0

Answer: Option B

Explanation:

The yeast and human beings are genetically different but some part of their genome is same.

The yeast and the human beings are similar in the way that they share the same genetic code. This is the reason when required the yeast can use a part of the human genome to compensate for the defective part of the gene.

The yeast and the human genome contains some part as in common so that human genome can be used in case of the emergency.

Hence, the correct answer is option B

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Westkost [7]

Answer:

35%

Explanation:

If two genes are 30 map units apart, 30% of the produced gametes will be recombinant.

A mating between an individual homozygous dominant for both traits (AB/AB) and one homozygous recessive for both traits (ab/ab) is conducted.

The F1 will be heterozygous for both genes: AB/ab.

The F1 progeny is then test-crossed to a homozygous recessive individual:

<h3>AB/ab X ab/ab</h3>

<u>The possible offspring will be:</u>

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Since 30% of all the gametes produced by the F1 individual will be recombinant, 70% will be parental. As there are two types of parental gametes, each of them will have a frequency of 35%.

<u>The offspring that will have a dominant phenotype for both traits has the genotype AB/ab with a proportion of 35%.</u>

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Vedmedyk [2.9K]
Germ cell's I believe. These are cells that includes half your genome in order to reproduce.
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