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valkas [14]
2 years ago
12

At a benefit​ concert, seven bands have volunteered to perform but there is only enough time for five of the bands to play. How

many lineups are​ possible?
Mathematics
1 answer:
Artist 52 [7]2 years ago
8 0
I believe the answer is 35.
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lukranit [14]
B just trust me bro I got you
4 0
2 years ago
Read 2 more answers
Express the calculation “four times as large as 124+645”
Effectus [21]

The calculation of the expression “four times as large as 124+645” end up in 1141.

<u>Step-by-step explanation:</u>

  • The question is asked to Express the calculation “four times as large as 124+645”.
  • The given statement can be written in the expression form to perform the calculations.

Here, the phrase 'four times' represents the multiplication of 4.

⇒ “four times as large as 124+645” = 4(124) + 645

So, the first step is to multiply 4 with 124.

⇒ 4 × 124

⇒ 496

The expression is now modified as “496+645"

We know that, the final result is the addition of the two numbers 496 and 645 which is calculated as

⇒ 496+645

⇒ 1141

Therefore, the calculation of the expression “four times as large as 124+645” end up in 1141.

7 0
3 years ago
Nathan is a recreational cyclist. He can travel 10 miles in one hour on his bicycle. Which graph represents the number of miles
PolarNik [594]

Answer:

See attachment for graph

Step-by-step explanation:

Given

1\ hr = 10\ miles

Required

The graph that shows the number of miles in x hours

We have:

1\ hr = 10\ miles

Multiply both sides by x

x * 1hr = 10miles * x

xhr=10x\ miles

So, the function is:

f(x) =10x

4 0
2 years ago
8 ÷ 1/3 I forgot how to do this please help me
Olegator [25]
Simplify the following:
8/(1/3)

Multiply the numerator of 8/(1/3) by the reciprocal of the denominator. 8/(1/3) = (8×3)/1:
8×3

8×3 = 24:
Answer:  24
5 0
3 years ago
Read 2 more answers
Please help me i need to find the area of shaded region please help me​
Montano1993 [528]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=13\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)\\A=84-24\\A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)\\A=96-16\\A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)\\A=80+16\\A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)\\A=225-81\\A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(4)(2)\\A=21-8\\A=13\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)\\A=(49\pi -33)\ in^2

6 0
3 years ago
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