I’m guessing you meant central tendency.
I’d say the mean is the best measure for period 2. This is because it doesn’t have any extremely low or high values which could distort the mean value.
If it did ie. 8, then I would choose median as it is less affected by anomalous results
Answer:
The width of the rectangle is 2.3 m
Step-by-step explanation:
Now, when we are asked to find the area of the rectangle, we will use the formula: 
. We should be given with at least two values, and then we can use the above formula and can find the third variable.
Now, we are given that the area of a rectangle is 12.65 
and the length measures 5.5 m
So the width is given as:
So this is the required with of the rectangle.
Answer:
4x-34
Step-by-step explanation: simplify to find your answer
Answer:
Step-by-step explanation:
Answer: f(120°) = (√3) + 1/2
Step-by-step explanation:
i will solve it with notable relations, because using a calculator is cutting steps.
f(120°) = 2*sin(120°) + cos(120°)
=2*sin(90° + 30°) + cos(90° + 30°)
here we can use the relations
cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)
sin(a + b) = cos(a)*sin(b) + cos(b)*sin(a)
then we have
f(120°) = 2*( cos(90°)*sin(30°) + cos(30°)*sin(90°)) + cos(90°)*cos(30°) - sin(90°)*sin(30°)
and
cos(90°) = 0
sin(90°) = 1
cos(30°) = (√3)/2
sin(30°) = 1/2
We replace those values in the equation and get:
f(120°) = 2*( 0 + (√3)/2) + 0 + 1/2 = (√3) + 1/2
