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ipn [44]
4 years ago
7

What kind of financial institutions does the Office of Thrift Supervision oversee?

Mathematics
1 answer:
xxTIMURxx [149]4 years ago
5 0
Savings and Loan Institutions.
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In the ordered pair (12, –7)
Dovator [93]
The Abscissa is -7 and the ordinate is 12
5 0
3 years ago
What is the domain of the square root function graphed below
Lina20 [59]

Answer:

Dominio de una Raíz cuadrada

Cuando tenemos una raíz, para estudiar su existencia debemos saber que una raíz existe si y solo sí el radicando (lo que está dentro de la raíz) sea mayor o igual a cero.

Por lo tanto deberemos estudiar el signo de lo que se encuentra dentro de la raíz; y determinar las zonas positivas y las raíces que son las zona de existencia de la función raíz o dominio de esta función.

Step-by-step explanation:

qsy

5 0
3 years ago
I need help on nine and 10 instructions say to solve these equations by cross multiplying
Aneli [31]

Answer:

  9.  a = -1

  10.  b = 20

Step-by-step explanation:

The term "cross multiplying" is used to describe the appearance of the result of multiplying both sides of the equation by the product of the denominators. The result is the left numerator is multiplied by the right denominator, and the right numerator is multiplied by the left denominator. The property of equality that supports this is the multiplication property of equality, which tells you the values of the variables are unchanged if you multiply both sides by the same thing. That multiplier is chosen so that it cancels the denominators.

__

<h3>9.</h3>

  \dfrac{2a-5}{3a-4}=\dfrac{2a-3}{3a-2}\\\\(3a-2)(2a-5)=(3a-4)(2a-3)\qquad\text{"cross multiply"}\\\\6a^2 -19a +10=6a^2-17a+12\qquad\text{expand}\\\\-2=2a\qquad\text{add $19a-6a^2-12$}\\\\\boxed{a=-1}\qquad\text{divide by 2}

__

<h3>10.</h3>

  \dfrac{b-2}{b-6}=\dfrac{b+2}{b-4}\\\\(b-4)(b-2)=(b-6)(b+2)\qquad\text{"cross multiply"}\\\\b^2-6b+8=b^2-4b-12\qquad\text{expand}\\\\20=2b\qquad\text{add $6b+12-b^2$}\\\\\boxed{b=20}\qquad\text{divide by 2}

_____

<em>Additional comments</em>

Here are the answer checks:

  9. (2(-1) -5)/(3(-1)-4) = (2(-1)-3)/(3(-1)-2) ⇒ -7/-7 = -5/-5 . . . yes

  10. (10 -2)/(10 -6) = (10 +2)/(10 -4) ⇒ 8/4 = 12/6 . . . yes

__

Sometimes this method of solving the problem will result in extraneous solutions. Those will generally be values of the variable that make one or more of the denominators be zero. You must be careful to exclude those values from any possible solution set.

5 0
3 years ago
Giving 15 points! Please help me with these two figures!
Oksana_A [137]
11. D. Square Pyramid
12. A. Cube
8 0
3 years ago
13. Simplify: (-5-√3)^2
Brilliant_brown [7]
I hope this helps you




(-5)^2+2. (-5)(-square root of 3)+('square root of 3)^2



25-10square root of 4+3



28-10square root of 3
4 0
3 years ago
Read 2 more answers
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