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3 years ago

What are two mixed numbers that have a sum of 3

Mathematics

2 answers:

GalinKa [24]3 years ago

8 0

The two mixed number are 1 1/2+ 1 1/2= 3

dezoksy [38]3 years ago

6 0

1 1/2 and 1 1/2( or 1.5+1.5) =3

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Find the perimeter and area

stepladder [879]

Answer:

32 times square root of 3. is the perimeter, area is 48 times square root of 3

Step-by-step explanation:

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3 years ago

A straight road crosses two parallel railway tracks. The angle between the road and the

Mumz [18]

<h3>Answer: 95 degrees</h3>

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Explanation:

I recommend drawing it out to see what's going on. See the drawing below.

In the diagram, both angles are in the northeast corner of their four-corner configurations. They are both congruent corresponding angles. So that's why the second angle is also 95 degrees.

Side note: we could replace "northeast" with any of the other directions on the compass (such as southwest). All that matters is that they are in the same configuration.

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3 years ago

What is the result of converting 35 ounces into pounds? Remember that 1 pound = 16 ounces.

worty [1.4K]

The answer should be A

5 0

3 years ago

Read 2 more answers

Please i need the step-by-step solution please thank you

Sergio [31]

Answer:

Question 6: -8

Question 7: C

Step-by-step explanation:

Question 6:

The reason question 6 is -8 is because of the distance in between each number, e.g -7 and -15. This is not to be confused with + 8 each time that would make the sequence 9, 18, 27.

Question 7:

The way we solve this question is using the nth term rule, whatever is before the n is the times tables we follow. So if it is 2n the sequence would be 2, 4, 6, 8 etc. However when we add something like the -2 we do the 2 times tables but this time we -2 for each one. Example: 2 - 2 = 0 so the first number of the sequence is 0, Example 2: 4-2 = 2 so the second number of the sequence is 2.

3 0

3 years ago

Read 2 more answers

How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?

defon

$\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1$

$(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1$

$\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2$

$\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3$

$\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}$

4 0

4 years ago