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s344n2d4d5 [400]
3 years ago
7

What's the answer??? idk ......

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0
So basically it is almost giving u the answer look were it say a - 0.4 then look up at 0/6 bit it behind it  a lil do that for all of the hope this helps

Rom4ik [11]3 years ago
3 0
Fin a common number all of the numbers shown have in common. Like multiply 7 x 5 x 6 and you get 210. and for .4 the simplified version of that in 2/5
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2028.863 rounded to the nearest hundredth
ASHA 777 [7]

Answer:

2028.863 to the nearest hundredth

The Number In The Hundredth Place Is 6 And The The Number Following Is 3 And Because Its Less Than 5, The 6 Will Remain.

So Its 2028.86

3 0
3 years ago
Read 2 more answers
3. Diego lives in a city and Anya lives in another city. Their houses are 164 miles apart. They both meet at their
liq [111]

Answer:

zfgggcvghh byhjmj

Step-by-step explanation:

ggjjjnnnnhugvb hh

6 0
3 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
The Millers plan on retiring soon. When they were first married they purchased 1,000 shares in a mutual fund that was at that ti
kozerog [31]

Answer: There is 680% increase for the fund.

Step-by-step explanation:

Since we have given that

Number of shares they purchased = 1000

Cost of per share at the time of their marriage = $10

So, Amount of fund will be

1000\times 10=\$10000

Cost per share after 30 years = $78

So, Amount of fund will be

78\times 1000=\$78000

Percentage of increase for the fund will be given as

\frac{78000-10000}{10000}\times 100=680\%

Hence, there is 680% increase for the fund.

8 0
3 years ago
Read 2 more answers
Find the variation constant and an equation of variation for the given situation.
Angelina_Jolie [31]

Answer:

\displaystyle y=14\cdot x

Step-by-step explanation:

<u>Directly Proportion</u>

It's said that y varies directly proportional as x, if:

y=k\cdot x

Where k is a constant of proportionality.

We know that y=7 when x=1/2.

Using the above condition, we can find the value of k:

\displaystyle 7=k\cdot \frac{1}{2}

Solving for k:

k=14

Thus, the equation is:

\boxed{\displaystyle y=14\cdot x}

6 0
3 years ago
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