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Varvara68 [4.7K]
3 years ago
6

What would happen if a virus could not find a host cell to invade?

Biology
2 answers:
Oliga [24]3 years ago
8 0

Answer: It will not be able to multiply

Explanation:

Virus are infectious agents that can live, survive and replicates inside a host cells. When virus enter a host cells makes the host cells to begin to replicates dna copies of the virus, thereby causing damage and harm. Virus cannot multiply outside a host because get sources from their host to replicate.

Monica [59]3 years ago
3 0

Answer:

it would not be able to multiply

Explanation:

Viruses lack the ability to replicate on their own, so if they don't invade the host cell and reprogram, they won't be able to multiply.

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How does the structure of DNA allow copies to be made?
hichkok12 [17]

Answer:

It's a double helix that can be unzipped, copied, and then replicated

5 0
3 years ago
Which represents deposition?<br>gas to solid<br>liquid to solid<br>liquid to gas<br>solid to gas​
Furkat [3]

Deposition is when a gas skips the step of becoming liquid and goes straight to a solid.

This means the answer is:

gas to solid

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4 0
4 years ago
There is a population of Drosophila flies in a small fruit shop. Due to sudden mutation, the eye color of some of the flies chan
galben [10]
The answer is <span>A. p2 = 0.36, 2pq = 0.48, q2 = 0.16.
</span>
Let's first distinguish alleles frequencies from genotypes frequencies:
p - a frequency of R allele,
q - a frequency of r allele,
p² - a frequency of RR genotype,
2pq - a frequency of Rr genotype,
q² - a frequency of rr genotype.

<span>The gene frequency of allele r changes from 0.38 to 0.40, thus:
</span>q = 0.40

Now, we will implement this in the following equation:
p + q = 1

If q = 0.40, then:
p + 0.40 = 1
⇒ p = 1 - 0.40
⇒ p = 0.60

Now, the frequencies of both alleles are know and it is easy to calculate the <span>genotype frequencies:
-</span> the frequency of RR genotype: p² = 0.60² = 0.36
- the frequency of Rr genotype: 2pq = 2 · 0.60 · 0.40 = 0.48
- the frequency of rr genotype: q² = 0.40² = 0.16

Therefore, the new genotype frequencies in that population are <span>p2 = 0.36, 2pq = 0.48, q2 = 0.16.</span>
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3 years ago
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They decrease because the zebra mussel were taking their resources. Leaving them nothing to eat.
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