<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
first the square root of 4 is 2 so we can sub that in.
now we have 2(2*2)^-2.
2 * 2 of course is 4
with 2(4)^-2, keep in mind that negative exponents just mean to "flip" the number and turn the exponents positive.
so 4^-2 is the same as 1/4^2 or 1/16.
finally 1/16 * 2 = 2/16. 2/16 simplified is 1/8.
Answer:
For E, each angle is 60° because its an equilateral triangle.
F is 45° for x, 135° for y, lastly z is 22.5°
