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Artyom0805 [142]
3 years ago
10

A professor is grading the final exam. He notices that the mean test score is 61, and the standard deviation is 10. The test sco

res were normally distributed. if there were 450 students in the data sample, how many would have a test score between 61 and 71? *Round your answer to the nearest full value.
Mathematics
1 answer:
charle [14.2K]3 years ago
3 0

Answer:

66666699999

Step-by-step explanation:

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Prove that the difference between a two-digit number and the product of its digits will always be a 2 digit number.
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Step-by-step explanation:

Let the two-digit number is xy

<u>This can be written as:</u>

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<u>The difference between the number and product of its digits is:</u>

  • d = 10x + y - xy

<u>Rewrite this as below:</u>

d = 10x - xy + y - 10 + 10 =

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<u>We see that:</u>

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  • 1 ≤ 10 - y ≤ 10 again according to the condition given above

<u>The value of d is then:</u>

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  • 10 ≤ d ≤ 90
<h3>Proved</h3>
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Hey can anyone help me on number B please?
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Complete the equation: 96 in =<br> yd.
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Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

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\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

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