If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
Answer:
D
Step-by-step explanation:
∠ 6 is formed by the 2 lines that intersect at D
then the vertex of ∠ 6 is D
Answer:
3.24m
Step-by-step explanation:
SOH
sin(26)=O/7.4
O=7.4 sin(26)
O=3.24 (3sf)
The answer is division because u divide 3 from both side of the equation so that make the answer B
X = -1
(-1, -5) The line is horizontal.
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