Answer:
41.67% probability that a student has a dog given that they have a cat
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: having a cat.
Event B: having a dog.
12 of 27 students have a cat:
This means that 
5 students who have a cat and a dog.
This means that 
What is the probability that a student has a dog given that they have a cat?
41.67% probability that a student has a dog given that they have a cat
Answer:
B
Step-by-step explanation:
The function's zeroes results in vertical asymptotes. As one is at x = 1 and the other at x = -2, the zeroes must be (x-1) and (x+2), which only B contains in the numerator.
The answer is 13 cm
a = height , b= base ,c = hypotenuse
a^2 + b ^2 = c ^2 ( theorem of Pythagoras)
(12cm)^2+ (5cm)^2 = hypotenuse
144cm^2 + 25 cm ^3 = hypotenuse
169cm^2 = hypotenuse
Square toot of 169cm ^2 = hypotenuse
Answer : 13 cm = hypotenuse
Answer:
Step-by-step explanation:
Michelle collected data on the weight of 200 apples at the farmer's market. Most weighed 0.30 –.40 pounds, but three weighed over a pound each. Michelle identified this as a striking deviation. What should she do with it?
urrence.
Step-by-step explanation:
Let the number of books of Physics be x . Then , No. of chemistry books =3.5x
Now , according to question :
x+3.5x=90
Or , 4.5x=90
Or , x=90/4.5
Or , x=20
Now ,
3.5x= 3.5×20
= 70
Therefore , there were 70 chemistry books and 20 physics books in that question bank.
