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2 years ago

14

GO DEEPER Write a statement about the

1 answer:

Degger [83]2 years ago

8 0

Answer:

the answer is true because it tells you why the statements Is that

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"Code" the things that match then simplify each expression <br><br> 75g + 34 - 17c - 80g + 22c

Karolina [17]

The answer is -5g+5c+34

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2 years ago

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1/3 x = 1/6 write answer as a fraction

Andrews [41]

Step-by-step explanation:

1/3x=1/6

x/3=1/6

cross multiply

6x=3

divide both sides by 6

x=3/6

x=1/2

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3 years ago

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How can you determine that a quadrilateral must be a parallelogram?

Temka [501]

If a quadrilateral has one pair of sides

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3 years ago

(a) Find the equation of the normal to the hyperbola x = 4t, y = 4/t at the point (8,2).

gtnhenbr [62]

The slope of the tangent line to the curve at (8, 2) is given by the derivative $\frac{dy}{dx}$ at that point. By the chain rule,

$\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}$

Differentiate the given parametric equations with respect to $t$ :

$x = 4t \implies \dfrac{dx}{dt} = 4$

$y = \dfrac4t \implies \dfrac{dy}{dt} = -\dfrac4{t^2}$

Then

$\dfrac{dy}{dx} = \dfrac{-\frac4{t^2}}4 = -\dfrac1{t^2}$

We have $x=8$ and $y=2$ when $t=2$ , so the slope at the given point is $\frac{dy}{dx} = -\frac14$ .

The normal line to the same point is perpendicular to the tangent line, so its slope is +4. Then using the point-slope formula for a line, the normal line has equation

$y - 2 = 4 (x - 8) \implies \boxed{y = 4x - 30}$

Alternatively, we can eliminate the parameter and express $y$ explicitly in terms of $x$ :

$x = 4t \implies t = \dfrac x4 \implies y = \dfrac4t = \dfrac4{\frac x4} = \dfrac{16}x$

Then the slope of the tangent line is

$\dfrac{dy}{dx} = -\dfrac{16}{x^2}$

At $x = 8$ , the slope is again $-\frac{16}{64}=-\frac14$ , so the normal has slope +4, and so on.

5 0

1 year ago

Help me pls <br> 9(x-y)=?

kaheart [24]

Answer:

9 (xy) =?

sulucion

9(xy)

=9 xy

4 0

3 years ago