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Andrews [41]
3 years ago
13

Morgan fills a 1-liter jar with water from the pond. She uses a 100-milliliter cup to scoop water out of the pond and pour it in

to the jar. How many times will Morgan scoop water from the pond to fill the jar?
Mathematics
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

Number of scoops required = 10

Step-by-step explanation:

Morgan fills a 1-liter jar with water from the pond.

Capacity of Jar = 1 liter

She uses a 100-milliliter cup to scoop water out of the pond and pour it into the jar.

Capacity of cup used to pour in to the Jar = 100 milliliter

We have relation

         1 liter = 1000 ml

         1 liter = 100ml x 10

         Capacity of Jar = Capacity of cup used to pour in to the Jar x 10

Number of scoops required = 10

Contact [7]3 years ago
5 0
1000 times I think
Hope it helped
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Can you help me plz in number 12,13,and 14 find the sum or difference.write your answer in simplest form plz explain good so I u
Maurinko [17]

Answer:

12. 11/18-1/6=4/9

13. 2/7+2/5=24/35

14. 3/4-3/10=9/20

Step-by-step explanation:

12. 11/18-1/6

11/18-1/6=11/18-(1/6)*(3/3)

11/18-1/6=11/18-(1*3)/(6*3)

11/18-1/6=11/18-3/18

11/18-1/6=(11-3)/18

11/18-1/6=8/18

Dividing the numerator and denominator of the fraction on the right side of the equation by 2:

11/18-1/6=(8/2)/(18/2)

11/18-1/6=4/9


13. 2/7+2/5

2/7+2/5=(2/7)*(5/5)+(2/5)*(7/7)

2/7+2/5=(2*5)/(7*5)+(2*7)/(5*7)

2/7+2/5=10/35+14/35

2/7+2/5=(10+14)/35

2/7+2/5=24/35


14. 3/4-3/10

3/4-3/10=(3/4)*(5/5)-(3/10)*(2/2)

3/4-3/10=(3*5)/(4*5)-(3*2)/(10*2)

3/4-3/10=15/20-6/20

3/4-3/10=(15-6)/20

3/4-3/10=9/20

8 0
3 years ago
Read 2 more answers
What is the derivative of ln(lnx^3)
chubhunter [2.5K]

the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , ln(lnx^3) , Let's differentiate it w.r.t x :

⇒ \frac{d(ln(lnx^3))}{dx}

Let lnx^3 = u

⇒ \frac{d(ln(u))}{dx}

⇒ \frac{1}{u} (\frac{d(u)}{dx} )

⇒ \frac{1}{u} (\frac{d(ln(x^3))}{dx} )

Let x^3=v

⇒ \frac{1}{u} (\frac{d(ln(v))}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )            

⇒ 3x^2(\frac{1}{u})(\frac{1}{v} )

Putting value of u & v we get:

⇒ 3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )

⇒ \frac{3}{x(lnx^3)}    { lnx^n = n(lnx)  }

⇒ \frac{3}{3x(lnx)}

⇒ \frac{1}{x(lnx)}

Therefore , the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

6 0
3 years ago
Hey can someone help with this question
egoroff_w [7]

Answer:

  • 1205 people per square miles

Step-by-step explanation:

  • Population = 10 511 215
  • Area = 8 723 square miles

<u>Population density is the number of people per unit of area:</u>

  • 10511215 / 8 723 = 1205 people per square miles

8 0
3 years ago
Read 2 more answers
( 15 points and brainliest) The volume of a tighter cylinder is 87.92 cm ^3 (that means cubed, or to the 3rd power). The radius
blsea [12.9K]
Given that:
Volume of cylinder, V= 87.92 cm³
Radius, r= 2 cm
π=3.14
Formula for volume of cylinder:
V=πr²h
Put values in the formula.
87.92=(3.14)(2)²h
87.92=(3.14)(4)h
87.92=12.56h
Divide both sides by 12.56
7=h
or
h=7 cm

Answer: Height of Cylinder is 7 cm.


6 0
3 years ago
Sarah has two similar regular pyramids with pentagon-shaped bases. The smaller has a scale factor of 2:3 when compared to the la
nordsb [41]

Answer:

(a) The volume of the pyramid 440.44 cube units

(b) No she doesn't

(c) The volume of the larger pyramid is 1,486.485 cube units

Step-by-step explanation:

The given parameters are;

The scale factor of the pyramids, S.F. = 2:3

The base area of the small pyramid, A_{b1} = 110.11 square units

The height of the small pyramid, h₁ = 12 units

(a) The volume of a pyramid, V = (1/3) × Area of base × The height of the pyramid

Therefore;

The volume of the small pyramid, V₁ = (1/3) × 110.11 square units × 12 units

V₁ = 440.44 cube units

The volume of the small pyramid, V₁ = 440.44 cube units

(b) No she does not have to go through all the hard work again to find the volume of the larger pyramid

She only has to make use of the scale factor relationships of the two pyramid to calculate the volume of the larger pyramid

The volume scale factor = (The linear scale factor)³

(c) The linear scale factor of the pyramids = 2:3 = 2/3

Therefore;

The volume scale factor of the pyramids = (2/3)³ = 8/27

To find the volume of the larger pyramid, V₂, from the volume of the smaller pyramid, V₁, we multiply the volume of the smaller pyramid, V₁,  by 27/8 as follows;

V₂ = V₁ × (27/8)

Therefore;

The volume of the larger pyramid, V₂ = 440.44 cube units × (27/8) = 1,486.485 cube units

The volume of the larger pyramid, V₂ = 1,486.485 cube units.

5 0
3 years ago
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