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3 years ago

Can you help me with all of them

Mathematics

1 answer:

Westkost [7]3 years ago

3 0

Well i numbered them across the top row then bottom 1-18...I got "shoots his mouth off" with no answer for #6 n+12 (blank space i presume and no answer for #15 x/3.

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If one card is drawn from a standard deck of 52 cards, what is the probability of selecting one of the 4 aces

AlladinOne [14]

The4 aces so probability = 4/52 = 1/13

5 0

3 years ago

Need help thanks!!!!!!

kherson [118]

Answer:

Step-by-step explanation:

$-----------------------------$

$Here's$ $how$ $we$ $solve$ $the$ equation

$-1.2\left(3-x\right)$ = $-1.8$

$-1.2\left(3-1.5\right)$ = $-1.8$

$-3.6+1.2\cdot1.5$ = $-1.8$

$1.2\cdot1.5$ = $-1.8$

$-----------------------------$

<em>Hope this helps! <3</em>

5 0

2 years ago

–21:(–2 – 5) + ( –14) + 6.(8 – 4.3)

Paladinen [302]

Did you mean -21(-2-5)+(-14)+6(8-4.3) ?
If that, the answer is 155.2:)) im sorry if im wrong:((

4 0

3 years ago

A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th

ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\$

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

$H_0: \mu=500\\\\H_a:\mu< 500$

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0

3 years ago

How can I find the volume of L shape blocks

Anvisha [2.4K]

The formula for volume is length multiplied by width multiplied by height
I hope this helps sorry if it doesn't :)

8 0

3 years ago