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3 years ago

Can you help me with all of them

Mathematics

1 answer:

Westkost [7]3 years ago

3 0

Well i numbered them across the top row then bottom 1-18...I got "shoots his mouth off" with no answer for #6 n+12 (blank space i presume and no answer for #15 x/3.

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A store is selling a TV for $389. This is %64 less than the regular price. What is the regular price?

nignag [31]

64% = $389
___ ____

100% X$ = Cross multiplication. (64x = 38900 = $607.81)

I rounded it.

Hope I become the brainliest answer.

4 0

3 years ago

Please help! This is super urgent I’m really tired and need to get my work done since it’s about to be due PLEASE ANSWER THIS IF

Anna71 [15]

Answer:

-12

Step-by-step explanation

√361 - 2(-3)² - /4-17/

19 - 18 -13= -12

8 0

3 years ago

tim can run three miles in 20 minutes if he maintain his speed how long will it take him to run 9 miles

Arlecino [84]

Answer:

60 minutes or 1 hour

Step-by-step explanation:

My picture is my worked out solution :)

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4 years ago

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

$Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}$

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

$P(B) = \frac{8}{12}$

$P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}$

<h3><u>Find </u><u> P(R | B)</u></h3><h3> $P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}$ </h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

$\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%$

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0

4 years ago

A coin is tossed, then a die is rolled, and the results are recorded. The number of possible outcomes for this event is

Alex

<span>The number of possible outcomes for a coin is 2.

</span>The number of possible outcomes for a die is 6.

The number of possible outcomes for a coin and a die is 2×6 = 12.

7 0

3 years ago

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