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Sauron [17]
3 years ago
13

Can you help me with all of them

Mathematics
1 answer:
Westkost [7]3 years ago
3 0
Well i numbered them across the top row then bottom 1-18...I got "shoots his mouth off" with no answer for #6 n+12 (blank space i presume and no answer for #15 x/3.
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Jonathon has a bag full of 14 balls to sell. He sells the baseballs for $2 dollars and the volleyballs for $5 and earns a total
olga55 [171]
X+Y=14
2x+5y=43
Those are the equations
7 0
3 years ago
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Two times x is 8 more than y. The sum of x and two times y is 14. Write two equations and graph to find the value of y.
Sauron [17]

Option B: $y=4$ is the value of y

Explanation:

It is given that "Two times x is 8 more than y". Writing it as expression, we have,

2x=8+y

It is also given that "The sum of x and two times y is 14". Writing it as expression, we have,

x+2y=14

To find the value of y, let us solve the two equations using substitution method.

From the equation 2x=8+y , let us find the value of x.

x=\frac{8+y}{2}

x=\frac{8}{2} +\frac{y}{2}

x=4+\frac{y}{2}

Now, substituting x=4+\frac{y}{2} in the equation x+2y=14 , we get,

4+\frac{y}{2}+2y=14

      4+\frac{5y}{2} =14

            $\frac{5 y}{2}=10$

            5y=20

              $y=4$

Thus, the value of y is $y=4$

8 0
3 years ago
Can anyone help me on this please?
romanna [79]

Answer:

x = 6

y = 12

z = 12√2

Step-by-step explanation:

3 0
3 years ago
Suppose that A and B are square matrices and that ABC is invertible. Show that each of A, B, and C is invertible.
Murljashka [212]

Answer:

You can proceed as follows:

Step-by-step explanation:

Suppose that the matrix ABC is invertible, and suppose that at least one of the matrices A,B,C is not invertible. Without loss of generality suppose that the matrix A is not invertible.  Remember the important result that a matrix is invertible if and only if its determinant is nonzero. Then,

\det (ABC)\neq 0.

On the other hand, the determinant of a products of matrices is the product of the determinants of the matrices, that is to say,

\det (ABC)=\det(A)\cdot \det(B)\cdot \det (C).

But we supposed that A is not invertible. Then \det (A)=0. Then \det(A)\cdot \det(B)\cdot \det (C)=0. This contradicts the fact that

\det (ABC)=\det(A)\cdot \det(B)\cdot \det (C)

and then the three matrices A,B,\, \text{and}\, C must be invertible matrices.

7 0
3 years ago
In a circle graph each section represents a different category<br> A)True<br> B)false
In-s [12.5K]
The answer is A) true 
5 0
3 years ago
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