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3 years ago

5

Identifying the strengths of a hero shows which character trait?

2 answers:

anzhelika [568]3 years ago

7 0

Courage.

Heros often take risks, you must have courage to take risks.

almond37 [142]3 years ago

6 0

Answer:

Courage

Step-by-step explanation:

Hero has some special characteristics which makes him hero

one of those characteristics of a hero is that a hero always shows courage and never fall down or run out from the situations instead he faces all the challenges with courage and never pocks down even in tricky situations.

a hero is that which helps the other when they need him in any situation or at any mode of life.a real hero does not care for his life .To save others he put his life in danger and shows courage.

all these qualities make a person a real hero.

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Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

At noon, a tank contained 6 cm of water. After several hours, it contained 3 cm of water. What is the percent decrease of water

tangare [24]

Answer:

50

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Simplfy the answer t-4t2/t2

Alenkasestr [34]

Answer:

t - 16

Step-by-step explanation:

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7 0

2 years ago

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I NEED HELP NOW!!! I ONLY HAVE 5 MIN TO TURN THIS IN

zubka84 [21]

Answer:

a)

28000 + 3000·x = 36000 + 2000·x --> x = 8 years

b)

28000 + 3000·8 = $52000

4 0

3 years ago

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Pls pls, pls help me with my math

Neko [114]

Answer:

Obviously only D is true

Note 2 x - 1 < 10 can be rewritten

2 X < 11 and

x < 5.5

So all of the values in the set would have to be less than 5.5

4 0

2 years ago