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Evgen [1.6K]
2 years ago
12

Find the measure of angle age

Mathematics
2 answers:
jok3333 [9.3K]2 years ago
6 0

Answer:

I think you forgot to add the picture.

Ivahew [28]2 years ago
4 0
Well if their was a photo, I might be able to help :)
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What is the simplified form of this equation f(x)=<br>x2 + 4x + 10​
seropon [69]

Answer:

6x + 10

Step-by-step explanation:

2+4=6

and 10 doesn't have an x next to it so it doesn't count

4 0
3 years ago
Read 2 more answers
Hulk left home and walked 8 blocks west. Then he turned and walked 6 blocks north. If each block is 500 ft. long, how far is Hul
son4ous [18]
The answer is 5000 ft 

His displacement is actually the hypotenuse (c) of the triangle with sides 6 blocks and 8 blocks.
According to the Pythagorean theoreme:
c² = a² + b²
c² = 6² + 8²
c² = 36 + 64
c² = 100
c = √100
c = 10 blocks

Since 1 block is 500ft long, then 10 blocks are 5000 ft long:
1 : 500ft = 10 : x
x = 10 * 500ft / 1 = 5000 ft
3 0
3 years ago
Can someone help me
Mashcka [7]

Answer:

whois someone? OH ! Right, That dude named Some Won . Sorry.. i'll let him answer.

Step-by-step explanation:

8 0
3 years ago
the ratio of adults to children attending a new exhibit at the museum was found to be 8:5. based on this ratio if 390 people att
LenaWriter [7]

999

why becuase thats the answer mine had

5 0
2 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
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