Check the picture below.
since in a rhombus the diagonals bisect each other, thus EC = EA.
now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%20%5Cbegin%7Bcases%7D%20b%3D8%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%288%29%2815%29%5Cimplies%20A%3D60%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20all%204%20triangles%7D%7D%7B4%2860%29%5Cimplies%20240%7D)
In left one)
the 3 angles are equal so the sides are equal then we can say

then x is 30÷11
the right one) is exactly similar
30kx - 6kx = 8
24kx = 8 /(÷8)
3kx = 1
x = 1/3k
Answer:
Some answers to the reducing fraction sheet
Q14 = 4/5 because divide 12 and 15 by 3
Q15=can't be reduced because 11 is a prime number so it can't be divided by anything
Q17=can't be reduced because 17 is a prime number
Q18=can't be reduced because 13 is a prime number
Q19=38/9 because 114 and 27 would be divided by 3
Q20= -1/1 because you would divide both 14,529 by itself would equal to - 1/1
I can only help you with this sheet I can't help you with the other one hope this was helpful! :)