Problem 1:
1) 3/5x-1 x 3/4=9/10
3x/5-1 x 3/4=9/10
2) 3x/5-1 x 3/4=9/10
3x/5-3/4=9/10
3) 3x/5-3/4=9/10
+3/4 +3/4
4) 3x/5=33/20
5) 5 x 3x/5= 5 x (33/20)
6) 3x=33/4
7) 3x=33/4
/3 /3
8) x=11/4
Problem 2:
1) 6/7+2/5x=-4/5
6/7+2x/5=-4/5
2) 6/7+2x/5=-4/5
-6/7 -6/7
3) 2x/5= --58/35
4) 5 x 2x/5= 5 x (--58/35)
5) 2x= --58/7
6) 2x= --58/7
/2 /2
x= --29/7
The difference is 6. Each number increases by 6 in the sequence.
2 + 6 = 8
8 + 6 = 14
14 + 6 = 20
20 + 6 = 26
Etc.
I would really appreciate it if I could get brainliest. Thanks!! =D
Hello, Marymack!
We know that in a geometric sequence defined by

and

, the sum can be calculated the following way:
The anwser is D)147 degrees
We have 5% and 6.5% acetic acid solutions and we need 200 ml of 6% acetic acid.
Set up two equations:
f means 5% and s means 6.5%
A) f + s = 200
B) .05f + .065s = (.06 * 200)
Multiplying equation A by -.05
A) -.05f -.05s = -10
B) .05f + .065s = 12 then adding both equations:
.015s = 2
<span>
<span>
<span>
we need 133.33</span> ml of 6.5% acetic acid and
66.67 ml of 5% acetic acid solution.
</span> </span>
Source:
http://www.1728.org/mixture.htm