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Amanda [17]
3 years ago
6

Evaluate. or Calculate the value

Mathematics
1 answer:
natta225 [31]3 years ago
3 0

-- The difference of 2 logs is the log of the quotient of their arguments.

             log(11) - log(6) = log(11/6)

-- 1/3 of the log of something is the log of its cube root.
 
                     1/3 log(8) = log(∛8) = log(2)
and
                     1/3 log(729) = log(∛729) = log(9)

-- If a bunch of logs all have the same base, then their sum
is the log of the product of the arguments.  So ...

         log(11) - log(6) + 1/3 log(8) + 1/3 log(729)  =

         log(11/6 times 2 times 9)  =

         log( 11*18 / 6 )  =  <em>log(33)</em>

                                      log(33) = about <em>1.519</em> (rounded)

============================================

The other way:

log(11) =                  1.0414
-log(6) =                  -0.7782
log(8) = 0.9031
       1/3(0.9031) =     0.3010
log(729) = 2.8627
           1/3(2.8627) = 0.9542
                              -----------
Adum up:                 <em>1.5184</em>

(Note:  Everything is rounded.)


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