Use the discriminant to determine how many real number solutions exist for the quadratic equations -4j+3j-28=0

1 answer:

8 0

<span>the correct equation is
- 4j² + 3j - 28 =0

ax² + bx + c,
a = -4, b=3 c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
The answer there is no real roots</span>

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