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2 years ago

Based on an average of 100 and a standard deviation of 10, what number on the standard normal curve matches

Mathematics

1 answer:

aliina [53]2 years ago

5 0

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Slove step-by-step (5+4)×2+6-(2×2)-1

Sladkaya [172]

1. (5 + 4) x 2 + 6 - (2 x 2) - 1
2. 9 x 2 + 6 - 4 - 1
3. 18 + 6 - 4 - 1
4. 24 - 4 - 1
5. 20 - 1
6. 19

3 0

2 years ago

The bottles of juice that Craig usually buys each have x ounces of juice in them. Another company makes bigger

Tanya [424]

Answer:

Step-by-step explanation:

I divided im not 100 percent sure tho

6 0

2 years ago

Which of the following statements uses the additive identity? 9 + 0 = 9 9 · 0 = 0 9 + 1 = 1 + 9 (9)(1) = (1)(9)

m_a_m_a [10]

<h3>Answer: 9+0 = 9</h3>

The additive identity is 0. If you add 0 to any number, then you get the same number as a result. In general, x+0 = x where x is a place holder for any number. For this problem, x = 9 so that's how 9+0 = 9.

4 0

2 years ago

Read 2 more answers

Is 5 in the solution of x+3>8 explain. Thank youuu

tester [92]

X would have to equal 6 or greater as if x was 5

5+3 is the same as 8

6 0

2 years ago

Read 2 more answers

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

2 years ago