The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
<em><u>Solution:</u></em>
Given the statement:
Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen
Let us first understand the given statement,
Let the number be "x"
" sum of a number and four" means x + 4
"Three sets of a sum of a number and four" translated to 3(x + 4)
"sum of seven times the same number and thirteen" means 7x + 13
<em><u>Thus the algebraic expression for given statement is:</u></em>

<em><u>Using distributive property in above expression</u></em>

Therefore,

<em><u>Combine the like terms</u></em>

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
First, change everything into minutes.
12 noon is 12 by 60 which = 720 minutes.
9am is 9 by 12 which = 540 minutes.
X is now your number of minutes before noon.So noon - x is the next step:
720 - x
20 minutes ago it was 720 - x - 20
720 - x - 20= 540 + 3x (3x because you're looking for 3 times as many minutes)
720 - 20 - 540=4x (you combine all the like numbers and variables)
160 = 4x
160/4= x
40 = x
Your answer is 40 minutes
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Constant is otherwise called term independent. It should not contain any other letters.
So, a constant without a variable best describes a constant.
Answer:
hi
Step-by-step explanation: