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elixir [45]
4 years ago
9

Natasha had 2356 beads , Lydia had 1176 beads and Munah had 1708 beads at first.After they each used an equal number of beads, N

atasha had 3 times as many beads as Lydia. How many beads did each of them use?
Pls help me with this.I am in desprate need​
Mathematics
2 answers:
Crank4 years ago
6 0

Answer:

Step-by-step explanation:let number of beads used by each be x

after use:

Natasha had 2356-x

Lydia had 1176-x

2356-x = 3(1176-x)

solve for x

Galina-37 [17]4 years ago
3 0

Answer:

586 beads.

Step-by-step explanation:

Suppose they each used x beads. We have the following equation:

2356 - x = 3(1176 - x)    Because Natasha had 3 times Lydia's beads.

2356 - x = 3528 - 3x

2x = 3528 - 2356 = 1172

x = 1172/2 = 586 beads.

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For the hypothesis test H0: μ = 10 against H1: μ >10 and variance known, calculate the Pvalue for each of the following test
Basile [38]

Answer:

a) p_v =P(Z>2.05)=1-P(z

b) p_v =P(Z>-1.84)=1-P(z

c) p_v =P(Z>0.4)=1-P(z

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Hypothesis

Null hypothesis: \mu=10

Alternative hypothesis: \mu >10

If the random variable is distributed like this: X \sim N(\mu,\sigma)

We assume that the variance is known so the correct test to apply here is the z test to compare means, the statistic is given by the following formula:

z_o=\frac{\bar X -\mu}{\sigma}

Since we have the values for the statistic already calculated we can calculate the p value using the following formulas:

Part a

p_v =P(Z>2.05)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(2.05,0,1,TRUE)"

Part b

p_v =P(Z>-1.84)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(-1.84,0,1,TRUE)"

Part c

p_v =P(Z>0.4)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(0.4,0,1,TRUE)"

Conclusions

If we use a reference value for the significance, let's say \alpha=0.05. For part a the p_v so then we can reject the null hypothesis at this significance level.

For part b the p_v>\alpha so then we FAIL to reject the null hypothesis at this significance level.

For part c the p_v>\alpha so again we FAIL to reject the null hypothesis at this significance level.

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