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otez555 [7]
3 years ago
14

I'm not sure what this means, please help me I'll give you 10 points ;)

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

<u>Answer:</u>

So all the possible solutions are:

  • \bold{523,~400,~379~and,~378.6}

<u />

<u>Solution Steps:</u>

<em>First you need to solve the real inequality to understand how to find the rest of the possible equations. </em>

<u>Add 78 to both sides:</u>

  • <u />78+78= Cancels Out
  • 300+78=378

<em>So now we know the real answer, but it ask for all possible answers. </em>

(Means anything larger than 300 when you plug it into x - 78 > 300.)

<u>Numbers that are greater than 378:</u>

  1.)  377-78=299 > 300  (False)

  2.)  523-78=445>300  (True)

  3.)  0-78=-78>300  (False)

  4.)  -62-78=-140>300  (False)

  5.)  400-78=322>300  (True)

  6.)  379-78=301>300  (True)

  7.)  222-78=144>300  (False)

  8.)  378.6-78=300.6>300 (True)

______________________________

 \bold{Hope~this~helps!}\\\bold{If~you~need~help~with~anything~else,~feel~free~to~ask!}\\\\\bold{~~~~~-TotallyNotTrillex}

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<span>Un cubo tiene seis caras.

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3 0
4 years ago
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How to solve -4{1-2x}-1=7x
mina [271]

Answer:

<h2>x = 5</h2>

Step-by-step explanation:

-4(1-2x)-1=7x\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-4)(1)+(-4)(-2x)-1=7x\\\\-4+8x-1=7x\qquad\text{combine like terms}\\\\8x+(-4-1)=7x\\\\8x-5=7x\qquad\text{add 5 to both sides}\\\\8x-5+5=7x+5\\\\8x=7x+5\qquad\text{subtract}\ 7x\ \text{from both sides}\\\\8x-7x=7x-7x+5\\\\x=5

7 0
3 years ago
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Find the area and perimeter of the room.. the vertices are 10,20 -10,20 -10,-10 10,-10
Ierofanga [76]
The numbers in this problem are ordered pairs, which are points on a graph.
These are (10, 20), (-10, 20), (-10, -10), and (10, -10).
To find the area and perimeter of this shape, you must first find the distance between each point.

Distance between (10, 20) and (-10, 20):
Since the y-value remains the same here, we just have to find the difference in x-values.
This means 10 - (-10)
A negative being subtracted is the same as a positive being added.
That means 10 - (-10) is the same as 10 + 10.
10 + 10 = 20, so the distance between (10, 20) and (-10, 20) is 20 units.

Distance between (-10, 20) and (-10, -10):
The x-values are the same here so just find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between the (-10, 20) and (-10, -10) is 30 units.

Distance between (-10, -10) and (10, -10):
The y-values are the same so just find the difference between the x-values.
10 - (-10) = 10 + 10 = 20
The distance between (-10, -10) and (10, -10) is 20 units.

Distance between (10, -10) and (10, 20):
The x-values are the same so find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between (10, -10) and (10, 20) is 30 units.

So now we know the side lengths of the room are 20 units, 30 units, 20 units, and 30 units.

To find the perimeter, add all the side lengths together.
20 + 30 + 20 + 30 = 100
The perimeter of the room is 100 units.

To find the area, multiply the length by the width.
The length is 20 units and the width is 30 units.
20 • 30 = 600
The area of the room is 600 units.

Final answers:
Perimeter = 100
Area = 600

Hope this helps!
7 0
3 years ago
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Damm [24]

Answer:

just practice time and again practice might not make perfect but it surely makes better. relying when your teacher only might not help you must mostly rely on your hard work and also have people at your disposal to help you including the said teacher hope you'll improve

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Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

The information provided is:

N=1500\\n=183\\\sigma=1.47\\\bar x=3.3

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

     =3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0
3 years ago
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