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Katarina [22]
2 years ago
10

What is the greatest common factor of 30y^8+10y^4 ? 10y^4 y^2 10y^8 20y^2

Mathematics
1 answer:
sesenic [268]2 years ago
6 0
<span>I think it's C.10y^8 hope this helps</span>
You might be interested in
Which expression is equivalent to 4(5 − 3) <br><br> 9 − 3<br><br> 8x<br><br> 20 − 12<br><br> 8 + 1
Ludmilka [50]
The correct answer is 20- 12
4 0
2 years ago
The sum of Ali and Mel's age is 39. If Mel is 3 years younger than twice Ali's age, how old is Mel?
olga55 [171]

Answer:

Age of Mel is 25 years.

Step-by-step explanation:

It is given that,the sum of Ali and Mel's age is 39. If Mel is 3 years younger than twice Ali's age.

Let 'x' be the Ali's age  and 'y' be the Mel's age

<u>To find the value of x and y</u>

sum of Ali and Mel's age is 39

⇒ x + y = 39    ------(1)

  Mel is 3 years younger than twice Ali's age

⇒ y = 2x - 3   -------(2)

⇒  2x - y = 3  -----(3)

(1) + (3) ⇒  

 x + y = 39

2x - y = 3

----------------

3x   = 42

x = 42/3 = 14

y = 2x - 3 = 14*2 - 3  = 25

Therefore the age of Ali = 14

Age of Mel = 25

4 0
3 years ago
Half of a set of the parts are manufactured by machine A and half by machine B. Ten percent of all the parts are defective. Six
baherus [9]

Answer:

The probability that a part was manufactured on machine A is 0.3

Step-by-step explanation:

Consider the provided information.

It is given that Half of a set of parts are manufactured by machine A and half by machine B.  

P(A)=0.5

Let d represents the probability that part is defective.

Ten percent of all the parts are defective.

P(d) = 0.10

Six percent of the parts manufactured on machine A are defective.

P(d|A)=0.06

Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective :

P(A|d) =\frac{P(A \cap d)}{P(d)}

P(A|d) =\frac{P(d|A)\times P(A)}{P(d)}\\P(A|d)= \frac{0.06\times 0.5}{0.10}

P(A|d)= 0.3

Hence, the probability that a part was manufactured on machine A is 0.3

8 0
2 years ago
81 is 37.5% of what number?
laila [671]

Hi,

81 is 37.5% of 216.

"1. We assume, that the number 37.5 is 100% - because it's the output value of the task.  

2. We assume, that x is the value we are looking for.  

3. If 100% equals 37.5, so we can write it down as 100%=37.5.  

4. We know, that x% equals 81 of the output value, so we can write it down as x%=81.  

5. Now we have two simple equations:

1) 100%=37.5

2) x%=81

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=37.5/81

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 81 is what percent of 37.5

100%/x%=37.5/81

(100/x)*x=(37.5/81)*x       - we multiply both sides of the equation by x

100=0.46296296296296*x       - we divide both sides of the equation by (0.46296296296296) to get x

100/0.46296296296296=x  

216=x  

x=216                          "

Have a great day!

3 0
2 years ago
Factor this trinomial. Your answer should consist of two binomials.
Sergeu [11.5K]
Y² + 8y - 33 :

Break  the expression  into groups for formula ax²+ bx+c :

= (y²- 3y) + (11y - 33 )

Factor y from y² - 3y =>  y (y - 3)

Factor out 11 from  11 y - 33 => 11 (y - 3)

= y ( y- 3 ) + 11 ( y - 3 )

Factor  out common  term (y - 3 ) :

= ( y - 3 ) ( y + 11 )

hope this helps!




5 0
2 years ago
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