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2 years ago

If i know that f(2)=4 what is another way I can write my answer

Mathematics

1 answer:

Ann [662]2 years ago

8 0

Answer:

I believe that it is (2,4)

Step-by-step explanation:

f(2) would be your y

4 would be your x

to write a point on a graph you wright (x,y)

(2,4)

You might be interested in

Find the additive inverse of 7/10

11111nata11111 [884]

$\huge\fbox{Hi~there!}$

Remember, a number's additive inverse is simply its opposite.

Let's say we have a number a.

The opposite of a is -a, and the opposite of -a is a.

Thus, the additive inverse of

$\displaystyle\frac{7}{10}$ is

$\displaystyle-\frac{7}{10}$

Hope it helps.

~Just a felicitous girl

#HaveAnAmazingDay

Feel free to ask if you have any doubts.

$\bf{-MistySparkles^**^*$

5 0

2 years ago

Tonya and Pearl each completed a separate proof to show that the alternate interior angles AKL and FLK are congruent. Who comple

Keith_Richards [23]

Answer: Pearl

Step-by-step explanation:

In step 2, she justified her step by the definition of vertical angles. However, angles AKL and GKB do not share a common side, meaning they are not adjacent angles.

4 0

2 years ago

Is a shoe store was having a back-to-school sale where you can buy six pairs of shoes for $52.62 if a large family decided to bu

hodyreva [135]

The family would buy the three pairs of shoes for $26.31 because you have to divide $52.62 in half since they bought half the amount of pairs of shoes that are given in the sale.

5 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2

AVprozaik [17]

Area of the rectangular mat = 12 x 4 = 48 in²

Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²

P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)

Answer: The probability of landing in one of the circles is 0.79.

7 0

3 years ago