A student took a system of equations, multiplied the first equation by 2 and the second equation by 3, then added the results to gether. Based on this, she concluded that there were no solutions. Which system of equations could she have started with? 1) 2x-4y=6
3x+6y=9
2) 3x+y=12
-3x+6y=6
3) -2x+4y=4
-3x+6y=6
4) 3x+6y=9
-2x-4y=4
1 answer:
Answer:
system 4.
Step-by-step explanation:
3x+6y=9
multiply by 2
6x+12y=18 ....(1)
-2x+-4y=4
multiply by 3
-6x-12y=12 ...(2)
add (1) and (2)
0+0=30
which is impossible .It has no solutions.
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Step-by-step explanation:
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Answer:
Parallel
Step-by-step explanation:
Answer:
R = sqrt 3 * (V /( pi * h))
V = 62.8
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h = 15
now we sub
R = sqrt 3 * (62.8 / (3.14 * 15)
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R = sqrt 3 * 1.33
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R = 1.9 rounds to 2 inches <===
Step-by-step explanation:
Y = cos(x)
sqrt(3)/2 = cos(30º)
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A is the answer have a nice day