A student took a system of equations, multiplied the first equation by 2 and the second equation by 3, then added the results to

Question

3 years ago

13

A student took a system of equations, multiplied the first equation by 2 and the second equation by 3, then added the results to

gether. Based on this, she concluded that there were no solutions. Which system of equations could she have started with?
1) 2x-4y=6
3x+6y=9

2) 3x+y=12
-3x+6y=6

3) -2x+4y=4
-3x+6y=6

4) 3x+6y=9
-2x-4y=4

Mathematics

1 answer:

egoroff_w [7] · Answer 1 · 2022-10-25T00:19:50+03:00

egoroff_w [7]3 years ago

3 0

Answer:

system 4.

Step-by-step explanation:

3x+6y=9

multiply by 2

6x+12y=18 ....(1)

-2x+-4y=4

multiply by 3

-6x-12y=12 ...(2)

add (1) and (2)

0+0=30

which is impossible .It has no solutions.