A student took a system of equations, multiplied the first equation by 2 and the second equation by 3, then added the results to
gether. Based on this, she concluded that there were no solutions. Which system of equations could she have started with?
1) 2x-4y=6
3x+6y=9
2) 3x+y=12
-3x+6y=6
3) -2x+4y=4
-3x+6y=6
4) 3x+6y=9
-2x-4y=4
1 answer:
Answer:
system 4.
Step-by-step explanation:
3x+6y=9
multiply by 2
6x+12y=18 ....(1)
-2x+-4y=4
multiply by 3
-6x-12y=12 ...(2)
add (1) and (2)
0+0=30
which is impossible .It has no solutions.
You might be interested in
2 11/16 I believe is the answer
Answer:
bc=eb and ca=fa
please tell me if this is actually the right answer
Step-by-step explanation:
bc=eb and ac=fa is wrong
bc=eb and ca=fa is right
cb=eb and ac=fa is wrong
ba=eb and ab=fa is wrong

=================================

=================================
:BrainliestBunch
Answer:
Yes
Step-by-step explanation:
The numbers both multiplied by 10
3 -6
30-60