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Romashka-Z-Leto [24]

4 years ago

13

All four functions below are quadratic functions. Which function has the greatest maximum value? Answer options attached in pict

ures. (10 points!!)

1 answer:

Taya2010 [7]4 years ago

3 0

There are no pictures?

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Find the sum of the finite geometric series<br> -3+6-12+24+-48+96-192+384

hammer [34]

255 (hope this helped)

3 0

4 years ago

!!! Use the sum of cubes identity to find the factors of the expression 8x^6 + 27y^3. Write your answer in the form of the expre

ki77a [65]

Answer:

(2x² + 3y)(4 $x^{4}$ - 6x²y + 9y²)

Step-by-step explanation:

A sum of cubes is factored in general as

a³ + b³ = (a + b)(a² - ab + b²) , thus

8 $x^{6}$ + 27y³

= (2x²)³ + (3y)³ with a = 2x² and b = 3y

= (2x² + 3y)((2x²)² - 2x²(3y) + (3y)²)

= (2x² + 3y)(4 $x^{4}$ - 6x²y + 9y²)

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"

qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that $\arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)$

Also, $-\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)$

This means our original expression is equal to:

$\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]$

Using the cosine addition formula, which states $\cos(a+b)=\cos a \cos b-\sin a \sin b$ , we get this itself is equal to:

$\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)$

Since $\sin^{2} \theta+\cos^{2} \theta=1$ , we know that:

$\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}$

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

$\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}$

3 0

2 years ago

There are 100 chickens on a farm. 63 of those chickens laid eggs on

mafiozo [28]

Answer:

63%

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Use substitution to show that 9+ 6(10-7x) is equivalent to 69-42x.

OverLord2011 [107]

9 + 60 -42x
9+60 = 69
= 69- 42x

5 0

4 years ago

Read 2 more answers