Answer:
120 deg
Step-by-step explanation:
Draw a horizontal line that passes vertices of 2 angles 125 deg and 115 deg.
This line is perpendicular with 2 vectors.
Apply the property of vertical angles and the sum of 3 angles in a triangle.
x = 180 - (125 - 90) - (115 - 90) = 120 deg
52s + 30b because 52 x s + 30 x b = 52s + 30b
Let
x---------------> distance from people living to the city center
we Know that
Zone 1 covers people living within three miles of the city center
Zone 1 ------------> [x < 3 miles]
Zone 2 covers those between three and seven miles from the center
Zone 2 ------------> [ 3 <= x < = 7 miles]
Zone 3 covers those over seven miles from the center
Zone 3 ------------> [ x > 7 miles]
<span>calculate the distance between two points to find the value of x
</span>
case A) point (0,0) point (3,4)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(4-0)² +(3-0)²]------> √[16+9]
x=√25-------------> x=5 miles
the answer Part A)
people living in (3,4)
x=5 miles -------------> covers Zone 2 [ 3 < =x <= 7 miles]
case B) point (0,0) point (6,5)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(5-0)² +(6-0)²]------> √[25+36]
x=√61-------------> x=7.81 miles
the answer Part B)
people living in (6,5)
x=7.81 miles -------------> covers Zone 3 [ x > 7 miles]
case C) point (0,0) point (1,2)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(2-0)² +(1-0)²]------> √[4+1]
x=√5-------------> x=2.23 miles
the answer Part C)
people living in (1,2)
x=2.23 miles -------------> covers Zone 1 [ x < 3 miles]
case D) point (0,0) point (0,3)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(3-0)² +(0-0)²]------> √[9]
x=√9-------------> x=3 miles
the answer Part D)
people living in (0,3)
x=3 miles -------------> covers Zone 2 [ 3 < =x <= 7 miles]
case E) point (0,0) point (1,6)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(6-0)² +(1-0)²]------> √[36+1]
x=√37-------------> x=6.08 miles
the answer Part E)
people living in (1,6)
x=6.08 miles -------------> covers Zone 2 [ 3 < = x <= 7 miles]
5,456 I just did this question good luck
Answer:
Step-by-step explanation:
Let the numbers be 
Such that:
Make z the subject
For their product to be maximum, we have:
Substitute in
Open bracket
Differentiate w.r.t x and y
Since the products are maximum, then 
For
Factorize:
Split
Make y the subject
For
---------------------------------------------------
Substitute y = 0
Factorize
---------------------------------------------------
Substitute 
Re-arrange
Factor x out
Divide through by x
Recall that:
Take LCM
Recall that:
Take LCM
Hence, the numbers are:
