When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
Answer:
K = 2/1
Step-by-step explanation:
Constant of proportionality can be found using any two given pair of values.
Constant of proportionality = y/x
Therefore, using (1, 2) , we have
Constant of proportionality = y/x = 2/1 = 2
Or it can be written as: k = ²/1 = 2
9.8t^2-49t+40=0
t=(49±√833)/19.6
t≈1.027, 3.97
1.027<t<3.97
Answer:
C
Step-by-step explanation:
When reflecting around the x axis, the x value stays the same and the y- will change.
Your Answer:
what type of question is this?
