Answer:
1. ![(\sqrt[5]{(m+2)})^{3} = (m+2)^{\frac{3}{5}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B%28m%2B2%29%7D%29%5E%7B3%7D%20%3D%20%20%28m%2B2%29%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D)
2. ![(\sqrt[3]{(m+2)})^{5} = (m+2)^{\frac{5}{3}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B%28m%2B2%29%7D%29%5E%7B5%7D%20%3D%20%20%28m%2B2%29%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D)
3. ![\sqrt[5]{(m)}^{3}+2 = m^{\frac{3}{5}}+2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%28m%29%7D%5E%7B3%7D%2B2%20%3D%20%20m%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%2B2)
4. ![\sqrt[3]{(m)}^{5}+2 = m^{\frac{5}{3}}+2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28m%29%7D%5E%7B5%7D%2B2%20%3D%20%20m%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%2B2)
Step-by-step explanation:
Recall that
![(\sqrt[n]{x})^{m} = (x^{\frac{m}{n}})](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Bx%7D%29%5E%7Bm%7D%20%3D%20%20%28x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%29)
Where 
is called radicand and n is called index
1. Root(5, (m + 2) ^ 3)
In this case,
n is 5
m is 3
x = (m + 2)
2. Root(3, (m + 2) ^ 5)
In this case,
n is 3
m is 5
x = (m + 2)
3. Root(5, m ^ 3) + 2
In this case,
n is 5
m is 3
x = m
4. Root(3, m ^ 5) + 2
In this case,
n is 3
m is 5
x = m
What's the smallest six-digit whole number possible?
It is 100000
try counting, six digits, right? if you even take 1 off from it, it's no longer six digits, so it is the smallest six-digit whole number possible.
what's the greatest 4-digit number?
It should be 9999
try adding 1 to it, it becomes five-digit number.
So, 9999 is the greatest 4-digit whole number possible.
To get a difference, subtraction.
100000 - 9999 = 90001
Just as a tip, for six digit number, 000000 does not work, as it is same as 0
Answer:
5/6
Step-by-step explanation:
<h2><u>
Plz Mark As Brainlest!</u></h2>
The standard form of a quadratic function is y = 3/2x² + 17/2x - 7
<h3>How to determine the
quadratic equation?</h3>
From the question, the points on the quadratic equation are given as
(2,4), (3,5) and (4,3)
The standard form of a quadratic equation is represented as
y = ax² + bx + c
So, we have
Point (2,4):
4a + 2b + c = 4
Point (3,5):
9a + 3b + c = 5
Point (4,3):
16a + 4b + c = 3
Solving using an online calculator. we have
a = 3/2, b = 17/2 and c = -7
Substitute a = 3/2, b = 17/2 and c = -7 in y = ax² + bx + c
y = 3/2x² + 17/2x - 7
Hence, the equation is y = 3/2x² + 17/2x - 7
Read more about quadratic equation at
brainly.com/question/1214333
#SPJ1
Answer:
23
Step-by-step explanation:
14x2=28-5=23
