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3 years ago

Answer pleaseeee ......

Mathematics

2 answers:

son4ous [18]3 years ago

8 0

It never decreases. hope that helped

7nadin3 [17]3 years ago

7 0

The cost never decreases as it is always going up based upon your x-value and your degree. Mark me as brainliest please.

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I need help on how to do this!!!?

liraira [26]

Let's say you had a cake that is cut into 5 equal slices. Then someone eats 2 of those slices. They ate 2/5 of the cake.

Now let's say you have another cake that you cut into 10 equal slices. If someone eats 4 of those ten, then they have eaten 4/10 = 2/5 of the cake.

Check out the diagram below to see a visual of how 4/10 and 2/5 are equivalent fractions.

Going from 2/5 to 4/10 has us multiply top and bottom by 2.

-----------

Similarly, 1/2 = 5/10 after multiplying top and bottom by 10

The original expression 2/5 + 1/2 turns into 4/10 + 5/10

Then you add the numerators to get 4+5 = 9, placing that over the common denominator of 10

<h3>Answer: 9/10</h3>

3 0

3 years ago

Can someone please help on number 20? WILL MARK YOU AS BRAINIEST. (can you also show how you do the problem?) :(

PSYCHO15rus [73]

Answer:

x =(22-√196)/6=(11-7)/3= 1.333

Step-by-step explanation:

(3x2 - 22x) + 24 = 0

The first term is, 3x2 its coefficient is 3 .

The middle term is, -22x its coefficient is -22 .

The last term, "the constant", is +24

Step-1 : Multiply the coefficient of the first term by the constant 3 • 24 = 72

Step-2 : Find two factors of 72 whose sum equals the coefficient of the middle term, which is -22 .

-72 + -1 = -73

-36 + -2 = -38

-24 + -3 = -27

-18 + -4 = -22 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -18 and -4

3x2 - 18x - 4x - 24

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (x-6)

Add up the last 2 terms, pulling out common factors :

4 • (x-6)

Step-5 : Add up the four terms of step 4 :

(3x-4) • (x-6)

Which is the desired factorization

Equation at the end of step 2:

(x - 6) • (3x - 4) = 0

STEP 3:

Theory - Roots of a product

3.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

5 0

3 years ago

PLS HELP HELP PLSZZZZZ

Dmitry_Shevchenko [17]

Answer:

cant see the pic.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

If y=12 when x=22 what is y when x=45

VLD [36.1K]

Answer:

y = 35

Step-by-step explanation:

3 0

2 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$