Answer:
1) See figure attached
2)
a) 
And if we replace we got:
b) 
And if we replace we got:
Step-by-step explanation:
Part 1
We can see the plot in the figure attached.
Part 2
a)
For this case we have two points 
And we want to find the distance travelled between these two points and we can use the following formula from the euclidian distance between two points:
And if we replace we got:
b)
Since it takes two seconds in order to go from (6.9) to (10,15) we can use the definition of velocity:
And if we replace we got:
You know from SOH CAH TOA that
.. tan(θ) = Opposite/Adjacent
Then the relations for any of these variables will be
.. Opposite = Adjacent * tan(θ)
.. Adjacent = Opposite / tan(θ)
.. θ = arctan(Opposite/Adjacent)
7. x is opposite.
.. x = (30 cm)*tan(26°) ≈ 14.63 cm
8, 9, 10, 14. x is opposite
11. x = arctan(30/60) ≈ 26.57°
12, 13, 15. x is the angle
south America = 2.2%
2.2% = 0.022
0.022 = 22/1000 which reduces to 11/500
-5.8c + 4.2 - 3.1 + 1.4c = -4.4c +1.1
Hope this helps! Ask me any questions if needed :)
Answer:
a. (-1, 3)
Step-by-step explanation:
The "glide" 4 units right and up is the transformation ...
(x, y) ⇒ (x+4, y+4)
The reflection across y=1 is the transformation ...
(x, y) ⇒ (x, 2-y)
Combined, you have the transformation ...
(x, y) ⇒ (x +4, 2-(y +4)) = (x +4, -2-y)
Then, ...
K(-5, -5) ⇒ K'(-5 +4, -2-(-5)) = K'(-1, 3)
