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2 years ago

A rectangular field is nine times as long as it is wide. If the perimeter of the field is 1700 feet, what

Mathematics

1 answer:

Leokris [45]2 years ago

6 0

Answer:

I. L = 10.35 feet

II. W = 93.15 feet.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangular field = 1700 feet

Translating the word problem into an algebraic expression, we have;

W = 9L

Mathematically, the formula for the perimeter of a rectangle is;

P = 2(L + W)

A. To write an equation;

X = P = 2(L + W)

B. To find the dimensions of the field;

207 = 2(L + 9L)

207 = 2L + 18L

207 = 20L

L = 207/20

L = 10.35 feet

To find the weight;

W = 9L

W = 9 * 10.35

W = 93.15 feet.

Therefore, the width of the field is

93.15 feet and the length of the field is

10.35 feet.

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statuscvo [17]

Given:

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To find:

The outliers of the given data set.

Solution:

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Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

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$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

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3 years ago

Consider two circular swimming pools. Pool A has a radius of 34 feet, and Pool B has a diameter of 20.92 meters. Complete the de

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Answer:

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3 years ago

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Answer:

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