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solmaris [256]
3 years ago
5

Find the missing angle I think...

Mathematics
2 answers:
lara [203]3 years ago
6 0

Answer:

Step-by-step explanation:

Since this is a test/homework, I'll give you a hint.

A triangle always is 180 degrees. If you add up all the sides, it should be 180.

A horizontal line is 180, if you add up the two sides (or the "line" that is crossing through the horizontal one) it'll be 180.

Just think of it like this: 180 is king. No matter what you add together, if its not 180, its wrong.

Hope this helps!  

slava [35]3 years ago
5 0
X=19

64+45= 109
180-109= 71
90-71=19
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If a=2,c=4 e=-6 then 3a-3(2c-e)
Gnom [1K]
The answer will be negative 36
HOPE IT HELPS,
 
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3 years ago
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In the playoffs, the Algenauts won their division playoff series 3 games to 1 and then beat their arch-rivals the Geometers in t
Natasha2012 [34]

Answer:

h = 48

Step-by-step explanation:

So they played 48 home games. They won 3/4, so they won 36 and lost 12.  

They played 48 away games. They won 2/3, so they won 32 and lost 16.  

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3 0
3 years ago
What is lim x→3 x^2 - x - 6/ x - 3
Kisachek [45]
<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

5 0
3 years ago
How to factorise<br><br><img src="https://tex.z-dn.net/?f=%20%7B8x%7D%5E%7B2%7D%20%20-%20%20xy%20-%20%7B7y%7D%5E%7B2%7D%20" id="
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3 years ago
What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


6 0
3 years ago
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