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3 years ago

The length of a rectangle is 2 feet more than 5 its width. The perimeter is 52 feet. Find the dimension of the rectangle

Mathematics

2 answers:

Ber [7]3 years ago

4 0

Answer: The length is 22 feet. The width is 4 feet.

Step-by-step explanation: Create an equation for the length: 2+5w=52.

Now combine the two sides to get 4+10w=52. Plug in some numbers that seem reasonable. I started with 4, checked my work and found that it was right. This problem is all about trial and error.

So, 4+10(4)= 44. Make sure to remember the width, so add 4 for each side: 44+8. 44+8=52. Hope this helps :)

Naily [24]3 years ago

4 0

Answer:

W= 4

L= 22

Step-by-step explanation:

1. L= 2+ 5w

W = W

2. 52= 2(L) + 2(W)

= 10 W + 4 + 2W

= 12W + 4

3. 52-4= 12 W

48 = 12W

4= W

4. L = 5W + 2

= 5 (4) +2

= 22

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3 years ago

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kakasveta [241]

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3 years ago

Please answer below :-)

Serjik [45]

Answer:

B. 88.8

Step-by-step explanation:

let x represent class y

(x+71.2)/2=80 multiply each side by 2

x+71.2=160 subtract 71.2 by both sides

x=88.8

trial an error

replace x with each of the numbers and see if it plugs in.

example:

(80.5+71.2)/2=80

151.7/2=80

75.85=80?

false. incorrect

another example:

(88.8+71.2)/2=80

160/2=80

80=80?

true. correct

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3 years ago