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Arturiano [62]
3 years ago
8

The length of a rectangle is 2 feet more than 5 its width. The perimeter is 52 feet. Find the dimension of the rectangle

Mathematics
2 answers:
Ber [7]3 years ago
4 0

Answer: The length is 22 feet. The width is 4 feet.

Step-by-step explanation: Create an equation for the length: 2+5w=52.

Now combine the two sides to get 4+10w=52. Plug in some numbers that seem reasonable. I started with 4, checked my work and found that it was right. This problem is all about trial and error.

So, 4+10(4)= 44. Make sure to remember the width, so add 4 for each side: 44+8. 44+8=52. Hope this helps :)


Naily [24]3 years ago
4 0

Answer:

W= 4

L= 22

Step-by-step explanation:

1. L= 2+ 5w

W = W

2. 52= 2(L) + 2(W)

= 10 W + 4 + 2W

= 12W + 4

3. 52-4= 12 W

48 = 12W

4= W

4. L = 5W + 2

= 5 (4) +2

= 22

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Answer:

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Step-by-step explanation:

From the question given:

FH = 9x + 15

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FG = ?

From the question given above, we can say that G is the midpoint of FH. This implies that:

FH = FG + GH

With the above idea in mind, we can obtain FG as follow:

FH = 9x + 15

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Rearrange

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FG = 9x - 5x + 15 - 4

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Since G is the midpoint of FH, it therefore means that FG and GH are equal i.e

FG = GH

With the above idea in mind, we can obtain the value of x as follow:

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FG = 4x + 11

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***Check ***

FH = 9x + 15

x = 7

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GH = 5x + 4

x = 7

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FG = 4x + 11

x = 7

FG = 4(7) + 11 = 28 + 11 = 39

FH = FG + GH

FH = 78

FG = 39

GH = 39

FH = FG + GH

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