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Arturiano [62]
3 years ago
8

The length of a rectangle is 2 feet more than 5 its width. The perimeter is 52 feet. Find the dimension of the rectangle

Mathematics
2 answers:
Ber [7]3 years ago
4 0

Answer: The length is 22 feet. The width is 4 feet.

Step-by-step explanation: Create an equation for the length: 2+5w=52.

Now combine the two sides to get 4+10w=52. Plug in some numbers that seem reasonable. I started with 4, checked my work and found that it was right. This problem is all about trial and error.

So, 4+10(4)= 44. Make sure to remember the width, so add 4 for each side: 44+8. 44+8=52. Hope this helps :)


Naily [24]3 years ago
4 0

Answer:

W= 4

L= 22

Step-by-step explanation:

1. L= 2+ 5w

W = W

2. 52= 2(L) + 2(W)

= 10 W + 4 + 2W

= 12W + 4

3. 52-4= 12 W

48 = 12W

4= W

4. L = 5W + 2

= 5 (4) +2

= 22

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Answer:

A) No, because the greatest common factor is 8y?, and the completely factored form is 8y2(4y2 - 6y + 3).

Step-by-step explanation:

Considering the expression

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From the elements in the parenthesis, 2 and y can still be factored out such that what will be left of each element

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