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3 years ago

Which equation is equivalent to 3=87/h

Mathematics

1 answer:

Mandarinka [93]3 years ago

8 0

29x3/h 3=87/h 87/29=h
h=87 h=29 h=3

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Select the best estimate for the quotient.75.1÷9=

Citrus2011 [14]

Answer:

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Step-by-step explanation:

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2 years ago

Select the correct answer.

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3 years ago

How many times bigger is 9x10^7 than 3x10^-2

irina [24]

Answer:

3×10^9

Step-by-step explanation:

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3 0

3 years ago

On a recent day 8 euros were worth 9 dollars and 24 euros were worth 24 dollars write an equation of the form y = kx

slavikrds [6]

<h3><u>Question:</u></h3>

On a recent day, 8 euros were worth $9 and 24 euros were worth $27. Write an equation of the form y = kx to show the relationship between the number of euros and the value in dollars.

<h3><u>Answer:</u></h3>

y = 1.125x is the equation to show the relationship between the number of euros and the value in dollars.

<h3><u>Solution:</u></h3>

Given that On a recent day 8 euros were worth 9 dollars and 24 euros were worth 24 dollars

Let "y" be the value in dollars

Let "x" be the number of euros

We have to write a equation in form of y = kx

<em><u>8 euros were worth 9 dollars</u></em>

"k" is found as follows:

$k = \frac{\text{value in dollars}}{\text{number of dollars}}$

$k = \frac{9}{8}$

Therefore, equation of y = kx is given as:

$y = \frac{9}{8}x$

$y = 1.125x$

To check the equation, use the another given value

24 euros were worth $27

$y = 1.125 \times 24\\\\y = 27$

Hence the equation y = 1.125x is correct

5 0

3 years ago

(x^2−x−6x^2−8x+16)/(x2−x−12)

erma4kov [3.2K]

-3 and 4 cannot be the values of x in the given expression

The expression is given as:

$\frac{(x^2-x-6x^2-8x+16)}{(x^2-x-12)}$

Start by equating the denominator to 0

$x^2 - x - 12 = 0$

Expand the above equation

$x^2 - 4x + 3x - 12 = 0$

Factorize the equation

$x(x - 4) + 3(x - 4) = 0$

Factor out x - 4

$(x + 3) (x - 4) = 0$

Split

$(x + 3)= 0\ or\ (x - 4) = 0$

Remove brackets

$x + 3= 0\ or\ x - 4 = 0$

Solve for x

$x =- 3\ or\ x = 4$

Hence, -3 and 4 cannot be the value of x in the given expression