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11Alexandr11 [23.1K]
4 years ago
7

Atoms from different substances can never combine with atoms from other substances. Disagree or agree reason why ?

Chemistry
1 answer:
uysha [10]4 years ago
5 0
Disagree, because they can come together to form a compound element. Hope it helped!
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Is this correct im so confused.
inysia [295]

Answer:

<em>the last option!!!!</em>

Explanation:

because its right

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3 years ago
WILL MARK BRAINLIEST AND THANK YOU!! PLEASE HELP!!!
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Answer:

c

Explanation:

6 0
3 years ago
Differentiated cells will first organize themselves into ________
ziro4ka [17]
It's TISSUES.
CELLS, TISSUES, ORGANS, ORGAN SYSTEM, NEW ORGANISM
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3 years ago
What mass of a 60.0-gram sample of N-16 will remain unchanged after 28.8 seconds?
Yanka [14]
The answer is 3.75 g.

Half-life is the time required for the amount of a sample to half its value.
To calculate the fraction of the sample remained unchanged, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of N-16 is 7.13.
So, we know:
t = 28.8 s
<span>t_{1/2} = 7.13 s

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{28.8 s}{7.13 s}
⇒ n=4.04
<span>⇒ n ≈ 4
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^4
<span>⇒x= \frac{1}{16}


If the fraction of the sample is 1/16 = 6.25%, then the mass of the sample could be calculated as:
x g : 6.25% = 60 g : 100% 
x = </span>
7 0
3 years ago
To standardize a hydrochloric acid solution, it was used as a titrant with a solid sample of sodium hydrogen carbonate, NaHCO3.
Ket [755]

Answer:

0.113 M

Explanation:

The reaction that takes place is:

  • NaHCO₃ + HCl →NaCl + CO₂ + H₂O

First we convert 0.3967 g of NaHCO₃ into moles, using its molar mass:

  • 0.3967 g ÷ 84 g/mol = 4.72x10⁻³ mol NaHCO₃

As 1 mol of NaHCO₃ reacts with 1 mol of HCl, in 41.77 mL of the HCl solution there were 4.72x10⁻³ moles of HCl.

With the <em>calculated number of moles and the given volume </em>we <u>calculate the concentration of the solution</u>:

  • Converting 41.77 mL ⇒ 41.77 mL / 1000 = 0.04177 L
  • Concentration = 4.72x10⁻³ mol / 0.04177 L = 0.113 M
6 0
3 years ago
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