3 years ago

Hi can someone help me with this question! First one to answer it I will make u brainliest

Chemistry

2 answers:

Scrat [10]3 years ago

8 0

Answer:

(B) Test 2

Explanation:

The entire substance changed, and turned into a liquid.

skad [1K]3 years ago

7 0

Answer:

Test 2

Explanation:

............................................

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g How many moles of NaOH are present in a sample if it is titrated to its equivalence point with 44.02 mL of 0.0885 M H2SO4? 2Na

Lisa [10]

Answer:

$n_{base}=3.90x10^{-3}molNaOH$

Explanation:

Hello!

In this case, since the sulfuric acid and sodium hydroxide react in a 1:2 mole ratio, given the reaction, we realize they have the following mole ratio at the equivalence point:

$2*n_{acid}=n_{base}$

Which in terms of concentrations and volumes is:

$2*M_{acid}V_{acid}=n_{base}$

Thus, we can plug in the volume and concentration of acid to find the moles of base:

$n_{base}=0.04402L*0.0885\frac{mol}{L} \\\\n_{base}=3.90x10^{-3}molNaOH$

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3 years ago

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BlackZzzverrR [31]

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4 years ago

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gayaneshka [121]

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3 years ago

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klemol [59]

Answer:

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