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3 years ago

Which number is a rational number

Mathematics

2 answers:

viktelen [127]3 years ago

6 0

The one in the top left is a rational number because 6/4 *6/4 is 36/16

Temka [501]3 years ago

4 0

The answer is a 36/16 and I hope this helps you and have a great day or great night

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Suppose you always eat a particular brand of cookies out of the standard sized package it comes in from the store. You notice th

Blababa [14]

Answer:

There are 91 cookies in the package of cookies

Step-by-step explanation:

The given parameter for the number of cookies are;

The number of cookies left when eating 3 at a time = 1 cookie

The number of cookies left when eating 5 at a time = 1 cookie

The number of cookies left when eating 7 cookies at a time = No cookie leftover

Let 'n' represent the number of cookies in the pack, let 'a', 'b', and 'c' be the multiples of 3s, 5s, and 7s in 'n', respectively, we have;

The number of cookies in the pack, n < 100

Therefore, we have;

3·a = n - 1

5·b = n - 1

7·c = n

∴ n - 1 is a multiples of 3 and 5 less than 100 which are;

15, 30, 45, 60, 75, and 90

Therefore, the possible values of 'n' are'

n = n - 1 + 1 = 15 + 1 = 16, 30 + 1 = 31, 45 + 1 = 46, 60 + 1 = 61, 75 + 1 = 75, 90 + 1 = 91

Multiples of 7 includes;

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, and 98

Therefore, n = 91 which is the number that appear simultaneously in both search

The number of cookies in a package = 91 cookies

3 0

2 years ago

An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random

Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters = 12

Total number of blue highlighters = 6

Total number of green highlighters = 4

Total number of orange highlighters = 3

So, the total number of highlighters = 12 + 6 + 4 + 3 = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1) = $\frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}$ = $\frac{12}{25}$

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1 = 11

Also, the number of blue highlighter = 6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2) =

$\frac{\textrm{Total number of yellow + Blue highlighters}}{\textrm{Total Highlighters}}$ = $\frac{17}{25}$

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0

3 years ago

The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers and together form a pyt

tatuchka [14]

24^2 + 45^2 = 51^2
576 + 2025 = 2601
2601 = 2601

The answer is B leg.

3 0

3 years ago

Read 2 more answers

-3(4x+5) a- 7x+15 b- 7x-15 c- -12x-15 d- -12x+15

Alexandra [31]

C, because everything inside the parenthesis is multiplied by -3.

3 0

3 years ago

Which of the following options correctly represents the complete factored form of the polynomial F(x)=x^4-3x^2-4?

Bumek [7]

Answer:

Step-by-step explanation:

Let's substitute a for x²:

x^4 - 3x² - 4

a² - 3a - 4

Now, this looks like something that is much more factorisable:

a² - 3a - 4 = (a - 4)(a + 1)

Plug x² back in for a:

(a - 4)(a + 1)

(x² - 4)(x² + 1)

The first one is a difference of squares, which can be factored into:

x² - 4 = (x + 2)(x - 2)

The second one can also be treated as a difference of squares:

x² + 1 = x² - (-1) = (x + √-1)(x - √-1) = (x + i)(x - i)

The answer is (x + 2)(x - 2)(x + i)(x - i), or D.

6 0

3 years ago

Read 2 more answers