Question

An airplane heading due east has a velocity of 210 miles per hour. A wind is blowing from the north at 38 miles per hour. What is the resultant velocity of the airplane? (Assume that east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.)

Answer 1

Answer:

The resultant velocity of the airplane is 213.41 m/s.

Step-by-step explanation:

Given that,

Velocity of an airplane in east direction, $v_1=210\ mph$

Velocity of wind from the north, $v_2=38\ mph$

Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.

We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :

$v=\sqrt{v_1^2+v_2^2}$

$v=\sqrt{(210)^2+(38)^2}$

v = 213.41 m/s

So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.