Actually Welcome to the Concept of the volumes.
Here given as, r= 6.2 mm, h = 10.8 mm, π=3.14
hence, the volume of the cone is
Volume = 1/3(πr^2h)
===> vol = 1/3(3.14*(6.2)^2*(10.8))
==> Vol = 1/3*(1303.57)
==> Vol = 434.52 mm^3
Hence the volume of the cone is 434.52 mm^3
Answer:
Simplifying
4p + -40 = 7(2p + 2)
Reorder the terms:
-40 + 4p = 7(2p + 2)
Reorder the terms:
-40 + 4p = 7(2 + 2p)
-40 + 4p = (2 * 7 + 2p * 7)
-40 + 4p = (14 + 14p)
Solving
-40 + 4p = 14 + 14p
Solving for variable 'p'.
Move all terms containing p to the left, all other terms to the right.
Add '-14p' to each side of the equation.
-40 + 4p + -14p = 14 + 14p + -14p
Combine like terms: 4p + -14p = -10p
-40 + -10p = 14 + 14p + -14p
Combine like terms: 14p + -14p = 0
-40 + -10p = 14 + 0
-40 + -10p = 14
Add '40' to each side of the equation.
-40 + 40 + -10p = 14 + 40
Combine like terms: -40 + 40 = 0
0 + -10p = 14 + 40
-10p = 14 + 40
Combine like terms: 14 + 40 = 54
-10p = 54
Divide each side by '-10'.
p = -5.4
Simplifying
p = -5.4
Step-by-step explanation:
brainliest????
Where is the table how can i solve the problem
Let's use the variable 'n' to represent the cost of a notebook and 'p' the cost of a pen.
If Kennel wants an equal number of notebooks and pens, we can create a group of one notebook and one pen, and the resulting cost will be 'n + p'
Then, to find the number of these groups Kennel can buy, we just need to divide the amount of money ($40) by the cost of the group of one notebook and one pen:
If the result is not a whole number, we need to round it down, since we can't spend more money than the budget of $40.
The answer is
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