I need a riddle with this number 5109

Micheal was asked to give examples of the identity property of addition and identity multiplication. Below are his answers.

xxMikexx [17]

Answer:

identity property of addition-

a+0=a

identity property of multiplication-

a*1=a

Step-by-step explanation:

i cant give u an exact answer as u didnt give Micheals answers so i just gave some examples about what addition and multiplication identity property should look like. Identity property's concept is to keep the same identity. Basically, "a" shouldnt change. In addition, to keep a the same all u hv to do is add 0 as anything plus 0 is the same. for multiplication, just multiply by 1. Hope this helps!!

5 0

3 years ago

Help me someone!!!!!!!!!!!!!!!!!!!!!!!

Julli [10]

Substitute answers in, a = 3 and b = 2.

(3^2 - 2^2)/(3+2)
= (9-4)/5
= 5/5
= 1

7 0

3 years ago

n an orchid show, seven orchids are to be placed along one side of the greenhouse. of the orchids, we see that the number of lin

NNADVOKAT [17]

Answer:

35

Step-by-step explanation:

7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we divide all options by the restrictions. The result is:

$\frac{7!}{4!*3!}$ = 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]

3 0

3 years ago

Andre tried to solve the equation 1/4(x + 12) = 2. What was his mistake? *

Umnica [9.8K]

Answer:

x=-4

Step-by-step explanation:

x+12=8

x=8-12

Andre did not multiple both by four to get the exact whole number. He also, didnt subtract 12 which is not possible due to it being multiplied by 1/4.

5 0

3 years ago

Please help, I’ll mark your answer as brainliest!

statuscvo [17]

Answer:

$(x-230)^2+(y-220)^2=6100$

Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the <u>distance formula</u>, which is really just the <u>Pythagorean Theorem</u> rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .

Finally, we have all of the components to create the equation of the circle. Plug-in 230 for $h$ , 220 for $k$ , and $\sqrt{6100}$ for $r$ .

The equation of the circle will be $(x-230)^2+(y-220)^2=6100$ .

Hope this helps :)

4 0

2 years ago