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hodyreva [135]
3 years ago
8

Can someone please help me with this?

Chemistry
1 answer:
Sergio039 [100]3 years ago
7 0
Amu valie on the top and abundsnce percent in decimals on the bottom for each isotope

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Suppose the half-life of element k is 20 minutes. if you have a 200 g sample of k, how much of element k will be left after 60 m
vodka [1.7K]
T=20 min
m₀=200 g
t=60 min

the mass of element through time t is:
m=m₀*2^(-t/T)

m=200*2^(-60/20)=25 g

25 grams of element will be left after 60 minutes

5 0
3 years ago
Read 2 more answers
H2SO3<br> What does this stand for?
ELEN [110]

Answer:

It means Sulfurous Acid

Explanation:

8 0
3 years ago
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A gas occupies a volume of 10 liters at a pressure of 0.5 atm. What is the pressure if the volume increases to 25.0 L? *
Rudik [331]

Answer:

0.2atm

Explanation:

By Boyle's law

P1V1=P2V2

0.5 x 10 = P2 x 25

therefore, P2= 0.2atm

7 0
3 years ago
Find the density if the mass is 20 grams and the volume is 10 mL?
tatiyna

Answer:

D= 2g/mL

Explanation:

20g/10ml= 2g/mL

5 0
2 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
3 years ago
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